Can someone help me with these problems step by step? It’s pre-algebra so it’s not rlly that hard.
1 answer:
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Answer:
There are 160 possible 4-piece lunch special meal.
Step-by-step explanation:
The lunch menu has a 4-piece lunch special which consists of a sandwich, soup, dessert and drink.
The available options for the sandwiches, soups, desserts and drinks are:
Sandwich: chicken, cheese and tomato, tuna, ham and lettuce, turkey
Soup: tomato, chicken noodle, vegetable
Dessert: ice-cream, piece of cake
Drink: tea, coffee, Coke, Sprite
So, the number of options are:
n (Sandwich) = n (A) = 5
n (Soup) = n (B) = 4
n (Dessert) = n (C) = 2
n (Drink) = n (D) = 4
There are 5 ways to select a sandwich, 4 ways to select a soup, 2 ways to select a dessert and 4 ways to select a drink.
The total number of possible 4-piece lunch special is:
Total number of 4-piece lunch special = n (A) × n (B) × n (C) × n (D)
Thus, there are 160 possible 4-piece lunch special meal.