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yarga [219]
3 years ago
5

Can someone help me with these problems step by step? It’s pre-algebra so it’s not rlly that hard.

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

11

Step-by-step explanation:

√121=11 so right answer is B

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How do you find a missing side of a triangle using SOH CAH TOA
katrin2010 [14]

Answer:

See explanation and attachment

Step-by-step explanation:

SOH CAH TOA is a mnemonic.

SOH means \sin \theta=\frac{Opposite}{Hypotenuse}

CAH means \cos \theta =\frac{Opposite}{Hypotenuse}

TOA means \tan \theta=\frac{Opposite}{Adjacent}

Given an angle and a side of a right angle triangle, you can use the appropriate ratio to find the missing side.

For instance, find x in the diagram in the attachment.

In this case the best ratio to use is TOA.

\tan 60\degree=\frac{\sqrt{3} }{x}

\implies x=\frac{\sqrt{3} }{\tan 60}

x=\frac{\sqrt{3} }{\sqrt{3} } =1

All the other ratio also follow the same pattern

NB: Your calculator in degree should give  \tan 60\degree=\sqrt{3}

3 0
3 years ago
572 to the nearest hundred
levacccp [35]
72 is 50 or above so you round it up.
<u />572 to the nearest hundred is <u>600</u>
3 0
3 years ago
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Find the area under the standard normal curve to the left of z = 1.5
DaniilM [7]

Answer:

0.9332

Step-by-step explanation:

3 0
3 years ago
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What is a slope on a graph
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<span> A line that never changes, so you can choose whatever two points you want and you will always get the same slope.

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3 years ago
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Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
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