You are given a slope and a point. It makes sense to use the point-slope form of the equation for a line. For slope m and point (h, k), that equation is ...
... y - k = m(x - h)
For m = 4 and (h, k) = (2, 1), your equation is
... y - 1 = 4(x - 2)
Answer:
yes, that is the correct answer. X is domain and Y is range so you are correct.
Step-by-step explanation:
Answer:
x+2 is the lowest turn
Step-by-step explanation:
2x+4 can be simplified into x+2
Answer:
The value of y by itself in the equation x+2y=10 is
![y=\frac{10-x}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B10-x%7D%7B2%7D)
Step-by-step explanation:
Given equation is x+2y=10 -------- (1)
To find y with given equation as below :
Equation (1) implies that x+2y=10
Subtracting the above equation by x we get
x+2y-x=10-x
x-x+2y=10-x
2y=10-x
Dividing by 2 on both sides we get
![\frac{2y}{2}=\frac{10-x}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2y%7D%7B2%7D%3D%5Cfrac%7B10-x%7D%7B2%7D)
![y=\frac{10-x}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B10-x%7D%7B2%7D)
Therefore the value of y is ![\frac{10-x}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B10-x%7D%7B2%7D)
Therefore the value of y by itself in the equation x+2y=10 is
![y=\frac{10-x}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B10-x%7D%7B2%7D)
Answer:
g^−1(7) = 6
h^−1(x) = x/2 + 3/2
(h^−1 ∘ h)(3) = 3
Step-by-step explanation:
If
g(6) = 7
Then
g^−1(7) = 6
h(x) = 2x - 3
Isolate x:
2x = h(x) + 3
x = h(x)/2 + 3/2
Replace x with h^−1(x) and h(x) with x:
h^−1(x) = x/2 + 3/2
We know that:
(h^−1 ∘ h)(x) = x
then:
(h^−1 ∘ h)(3) = 3