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Studentka2010 [4]
3 years ago
10

Which state(s) of matter have no definite shape or volume? liquids and solids liquids and gasses gasses solids

Physics
2 answers:
Alex777 [14]3 years ago
8 0

Answer:

Liquid has a defined volume but undefined shape

Explanation:

Explanation:

Solid has specific shape and volume

Liquid has specific volume but no specific shape

Gases have no specific volume and no specific shape

So correct answer is liquid.

DENIUS [597]3 years ago
6 0

Answer:

C on edge

Explanation:

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Through spectroscopy.  Each atom in a gas absorbs and emits light at very specific and unique frequencies.  Heating up a gas causes it to glow at these frequencies. If you put the light from a mercury lamp, for example, through a prism there will not be a rainbow.  There will only be specific bands of light at certain colors.  
On the other hand, white light comes from the sun.  The inner part of the sun creates white light as it isn't just a gas state (this specific choosing of frequencies is a gaseous phenomenon) but the atmosphere of the sun is a gas.  So when the white light passes through it, it absorbs specific frequencies specific to the elements in the gas.  These get scattered (released at random directions) and so many of them don't reach our telescopes.  So in a rainbow from stars (including the sun) have dark bands at specific frequencies.  You need equipment to focus and see the spectrum closely to notice this.  But the missing frequencies are the EXACT frequencies that the gas of the sun's atmosphere would release if heated in a lamp.  
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A monarchy is the type of government that the colonist do not want true or false
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4 years ago
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the ________ of a photon with a wavelength of ________ nm
Colt1911 [192]
The energy levels of the hydrogen atom are quantized and their energy is given by the approximated formula
E=-  \frac{13.6}{n^2} [eV]
where n is the number of the level.

In the transition from n=2 to n=6, the variation of energy is
\Delta E=E(n=6)-E(n=2)=-13.6 ( \frac{1}{6^2}- \frac{1}{2^2}  )[eV]=3.02 eV
Since this variation is positive, it means that the system has gained energy, so it must have absorbed a photon.

The energy of photon absorbed is equal to this \Delta E. Converting it into Joule,
\Delta E=3.02 eV=4.84 \cdot 10^{-19}J
The energy of the photon is
E=hf
where h is the Planck constant while f is its frequency. Writing \Delta E=hf, we can write the frequency f of the photon:
f= \frac{\Delta E}{h}= \frac{4.84 \cdot 10^{-19}J}{6.63 \cdot 10^{-34}m^2 kg/s}=7.29 \cdot 10^{14}Hz

The photon travels at the speed of light, c=3 \cdot 10^8 m/s, so its wavelength is
\lambda =  \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.29 \cdot 10^{14}Hz}=4.11 \cdot 10^{-7}m=411 nm

So, the initial sentence can be completed as:
The n = 2 to n = 6 transition in the bohr hydrogen atom corresponds to the "absorption" of a photon with a wavelength of "411" nm.
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