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horrorfan [7]
3 years ago
12

Has anyone have a friend that became so close to you and then she or he started ignoring you for the rest of the time and even b

eing close to you?
Mathematics
1 answer:
Alex787 [66]3 years ago
3 0

Answer:

yeah it sucks I'm sorry that happened to you. it'll get better. never be friends with that toxic person again.

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What is 76/10 in a mixed number??
cestrela7 [59]
A mixed number is in the form x y/z while a improper fraction (76/10) is in the form y/z. We can separate the fraction into two parts. One is 70/10 which = 7 and the other is 6/10 which simplifies to 3/5. So, in order to express 76/10 as a mixed number we must express it as 7 3/5 or 7 6/10. 7 3/5 is equal to 7 6/10.

I hope this helped you!  
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5 0
3 years ago
Part of a W-2 is shown.
sweet-ann [11.9K]

Answer:

$ 4466.83

Step-by-step explanation:

It says "Federal tax withhold" with the amount.

7 0
3 years ago
Read 2 more answers
What is the answer to<br> y+2=5
Semenov [28]
5-2=3 so therefore y=3
Remember to work backwards and use opposite operations.
5 0
3 years ago
Read 2 more answers
The vertices of a rectangle are R(-5, -5), S(-1, -5), T(-1, 1), and U(-5, 1). a translation, R to the point (-4,2). Find the tra
Nikitich [7]
Translation:
R ( - 5, - 5 ) → R` ( - 4, 2 )
- 4  = - 5 + 1,   2 = - 5 + 7;
The translation rule:
( x , y ) → ( x + 1, y + 7 )
Coordinates of the point U are (- 5, 1 )
- 5 + 1 = - 4,  1 + 7 = 8
The image of U is :
U` ( - 4, 8 )
4 0
3 years ago
Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.
FrozenT [24]
You have shared the situation (problem), except for the directions:  What are you supposed to do here?  I can only make a educated guesses.  See below:

Note that if    <span>ax^2+bx+5=0    then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers.  If this is the case, then the discriminant,    b^2 - 4(a)(c), must be positive.  Since c = 5, 

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then 

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

         - b plus sqrt( b^2 - 20a )
d =  ------------------------------------
                      2a

and

 </span>         - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
                      2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b."  Before going into that, however, I'm asking you to share the rest of the problem statement.  What, specificallyi, were you asked to do here?

7 0
3 years ago
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