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3 years ago

Part of a W-2 is shown.

Mathematics

2 answers:

pickupchik [31]3 years ago

8 0

Answer:

4466.83

Step-by-step explanation:

it tells you the federal tax withheld is 4466.83

sweet-ann [11.9K]3 years ago

7 0

Answer:

$ 4466.83

Step-by-step explanation:

It says "Federal tax withhold" with the amount.

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From an aeroplane vertically above a straight horizontal plane, the angles of depression of two consecutive kilometres stones on

Airida [17]

You have to build the triangles.

They are such that:
h is the common height
x is the horizontal distance from the plane to one stone
Beta is the angle between x and the hypotenuse

Then in this triangle: tan(beta) = h / x ......(1)

1 - x is the horizontal distance from the plane to the other stone
alfa is the angle between 1 - x and h

Then, in this triangle: tan (alfa) = h / [1 -x ] ...... (2)

from (1) , x = h / tan(beta)

Substitute this value in (2)

tan(alfa) = h / { [ 1 - h / tan(beta)] } =>

{ [ 1 - h / tan(beta) ] } tan(alfa) = h

[tan(beta) - h] tan(alfa) = h*tan(beta)

tan(beta)tan(alfa) - htan(alfa) = htan(beta)

h [tan(alfa) + tan(beta) ] = tan(beta) tan (alfa)

h = tan(beta)*tan(alfa) / (t an(alfa) + tan(beta) )

4 0

3 years ago

Surface area of a box 12 x 6 x 9.5

Ber [7]

9514 1404 393

Answer:

486 square units

Step-by-step explanation:

Use the surface area formula with the given numbers.

SA = 2(LW +H(L +W))

SA = 2(12·6 +9.5(12 +6)) = 2(72 +9.5(18)) = 486

The surface area of the box is 486 square units.

4 0

3 years ago

What's 27-18r using distributive property

solniwko [45]

The distributive property: a(b - c) = ab - ac

27 - 18r = 9·3 - 9·2r = 9(3 - 2r)

8 0

3 years ago

WILL MARK BRAINLIEST! Shelly served the volleyball over the net 17 out of 25 times. What is her percentage of serving the ball o

Tju [1.3M]

Answer

68℅

Explanation

17/25 =

17 ÷ 25 =

0.68 =

0.68 × 100/100 =

0.68 × 100% =

(0.68 × 100)% =

68%;

Hope that this helps you and have a great day :)

8 0

3 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago