Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
Simplifying-
(6d^2)(-7d)=
= -(42d^2)(d)
=-42d^3
I am sure it is (1,4) hope this helps
Answer:
h=(c/25)-4
Step-by-step explanation:
c-100 = 25h. "/25"
(c/25)-4 = h
8x+6? Are you asking us to write out the equation?
