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worty [1.4K]
3 years ago
9

PLEASE HURRY WILL MARK BRAINLIEST!!!

Mathematics
2 answers:
Mashcka [7]3 years ago
7 0
The answer to your question is D
LekaFEV [45]3 years ago
3 0

Answer:

-7y+8x

Step-by-step explanation:

-2y-x-5y+9x

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ILL GIVE BRAINLIEST PLSSSS HELP BASICALLY EVERYTHING IS IN THE PICTURE IF YOU ANSWER THIS WRONG OR PUT RANDOM WORDS OR A LINK I
Maksim231197 [3]

Answer:

4th one I believe, can I get support?

7 0
3 years ago
Read 2 more answers
Find the y-intercept for the line represented by this equation.
sashaice [31]

Answer:

A) (0,0)

Step-by-step explanation:

1.) graph the equation, 3x+2y = x+y

2.) the line intersects (0,0) on the coordinate plane

5 0
3 years ago
Help please :(. :( :(.,,,,,,,,,,,,,,,,
Volgvan

Answer:

  • y-intercept: y=9
  • zeros: x= -3, -1, 1, 3

Step-by-step explanation:

The y-intercept is where the graph crosses the y-axis. On this graph, that is just below y=10. A reasonable estimate* of the y-intercept is y=9.

__

The zeros are those places on the graph where y=0. The line y=0 is the x-axis, so the zeros are the x-values of the places where the graph crosses the x-axis. Those points are clearly labeled: x = -3, -1, 1, 3.

_____

* Knowing the zeros, you can write a factored-form equation for the graph:

  y = (x +3)(x +1)(x -1)(x -3)

You can substitute x=0 in this equation to see what the y-intercept would be:

  3×1×-1×-3 = 9

That is, with no scale factor applied to the function, its y-intercept would be 9. This is the same value we estimated above, so it is reasonable to assume that value is correct.

8 0
4 years ago
Please help me with these two
Luda [366]

Answer:

D

Step-by-step explanation:

4 0
3 years ago
Can the following expressions be written in a simpler forms? If yes, write an expression for each problem. If not, explain why w
Alona [7]

Answer:

Both of them can be simplified.

Recall that 4 = 2^2.

2^7 / 4^2 = 2^7 / (2^2)^2 = 2^7 / 2^4 = 2^(7-4) = 2^3 = 8

Similarly, 2^7 / 2^4 = 2^(7-4) = 2^3 = 8

The answers to both exercises are 8.

6 0
3 years ago
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