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yuradex [85]
3 years ago
13

Which of the following numbers is irrational?

Mathematics
1 answer:
zalisa [80]3 years ago
3 0

Answer:

square root of 5 my dude

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The ascent can be modeled by a different proportional relationship y=kx. What is the value of k in this case?
mote1985 [20]

Answer: the the answer

35814/3600

4 0
3 years ago
Solve questions 15,16,17, and 18. Will give Brainliest!! Please!!! Show minimal work!
SVEN [57.7K]

15. The terminal side of \frac{3\pi}{2} intercepted the unit circle at:

(0,-1).

This implies that:

(\cos \frac{3\pi}{2}, \sin \frac{3\pi}{2}=(0,-1)

This implies that:

\cos \frac{3\pi}{2}=0,\:and\: \sin \frac{3\pi}{2}=-1

16) We have that: \cot \theta =-\frac{6}{7}.

We illustrate this on the right triangle and apply the Pythagoras Theorem as follows:

h^2=6^2+7^2

h^2=36+49

h^2=85

h=\sqrt{85}

Using the mnemonics SOH-CAH-TOAH, we have:

\sin \theta=-\frac{Opp}{Hyp}=-\frac{7}{\sqrt{85} }=-\frac{7\sqrt{85} }{85}

\cos \theta=\frac{Adj}{Hyp}=\frac{6}{\sqrt{85} }=\frac{6\sqrt{85} }{85}

\tan \theta=-\frac{Opp}{Adj}=-\frac{7}{6}}

\csc \theta=-\frac{Hyp}{Opp}=-\frac{\sqrt{85} }{7}

\sec \theta=\frac{Hyp}{Adj}=\frac{\sqrt{85} }{6}

17. We want to verify that: sin^4x-sin^2x=cos^4x-cos^2x

Verifying from the LHS

\sin^4x-sin^2x=(sin^2x)^2-sin^2x

Recall that from the Pythagorean identity:\sin^2x=1-\cos^2x

\sin^4x-sin^2x=(1-cos^2x)^2-(1-\cos^2x)

\sin^4x-sin^2x=1-2cos^2x+\cos^4x-1+\cos^2x

\sin^4x-sin^2x=\cos^4x-\cos^2x

18.  We have:

\tan^2x\sec^2x+2\sec^2x-\tan^2x=2

\tan^2x\sec^2x+2\sec^2x-\tan^2x-2=0

\sec^2x(\tan^2x+2)-1(\tan^2x+2)=0

(\sec^2x-1)(\tan^2x+2)=0

When (\sec^2x-1)=0, we have

x=0,\pi

When \tan^2x+2=0, \tan^2x=-2

We can see this is not defined for all real values of x.

6 0
3 years ago
The scores on a Psychology exam were normally distributed with a mean of 67 and a standard deviation of 8. Create a normal distr
Trava [24]

Answer:

(a) The percentage of the scores were less than 59% is 16%.

(b) The percentage of the scores were over 83% is 2%.

(c) The number of students who received a score over 75% is 26.

Step-by-step explanation:

Let the random variable <em>X</em> represent the scores on a Psychology exam.

The random variable <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 67 and standard deviation, <em>σ</em> = 8.

Assume that the maximum score is 100.

(a)

Compute the probability of the scores that were less than 59% as follows:

P(X

                =P(Z

*Use a <em>z</em>-table.

Thus, the percentage of the scores were less than 59% is 16%.

(b)

Compute the probability of the scores that were over 83% as follows:

P(X>83)=P(\frac{X-\mu}{\sigma}>\frac{83-67}{8})

                =P(Z>2)\\\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the percentage of the scores were over 83% is 2%.

(c)

It is provided <em>n</em> = 160 students took the exam.

Compute the probability of the scores that were over 75% as follows:

P(X>75)=P(\frac{X-\mu}{\sigma}>\frac{75-67}{8})

                =P(Z>1)\\\\=1-P(Z

The percentage of students who received a score over 75% is 16%.

Compute the number of students who received a score over 75% as follows:

\text{Number of Students}=0.16\times 160=25.6\approx 26

Thus, the number of students who received a score over 75% is 26.

5 0
4 years ago
(math)
slega [8]

Answer:

c rectangle I'm pretty sure

5 0
3 years ago
Lesson20 homework2.39t
gulaghasi [49]
Can you send
picture or the question...please?
8 0
4 years ago
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