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Tomtit [17]
3 years ago
11

Can the following expressions be written in a simpler forms? If yes, write an expression for each problem. If not, explain why w

hy not. exercise 2⁷/4²= 2⁷/2⁴=​
Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

Both of them can be simplified.

Recall that 4 = 2^2.

2^7 / 4^2 = 2^7 / (2^2)^2 = 2^7 / 2^4 = 2^(7-4) = 2^3 = 8

Similarly, 2^7 / 2^4 = 2^(7-4) = 2^3 = 8

The answers to both exercises are 8.

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3. Write a similarity statement and state the scale<br> factor for the triangles.
ivann1987 [24]

Answer:

AA SIMILARITY statement

SSS similarity statement is also possible.

Step-by-step explanation:

In \:  \triangle CBA  \: and \:  \triangle TVU \\  \angle B \cong \angle V... (given) \\\angle A \cong \angle U... (given) \\\therefore \triangle CBA \sim \triangle TVU... (By AA\: Postulate)  \\

5 0
4 years ago
The question is in the picture.
bogdanovich [222]
Just download photomath bro, does everything for you.

3 0
3 years ago
PLEASE HELP me with this question
boyakko [2]

Answer:

EC/BC = DE/AB

Step-by-step explanation:

There are multiple answers for this, but this should work as well. EC is proportional to BC, and AB is proportional to DE, so one answer is: EC/BC = DE/AB

6 0
2 years ago
Bit transmission errors between computers sometimes occur, where one computer sends a 0 but the other computer receives a 1 (or
lana66690 [7]

Answer:

(a) Probability that a triplet is decoded incorrectly by the receiving computer. = 0.010

(b)

(1 – p) = 0.010

(c)

E(x) = 25000 x 0.010

     = 259.2

Explanation has given below.

Step-by-step explanation:

Solution:

(a) Probability that a triplet is decoded.

2 out of three

P = 0.94, n = 3

m= no of correct bits

m   bit (3, 0.94)

At p(m≤1) = B (1; 3, 0.94)

 = 0.010

(b) Using your answer to part (a),

(1 – p) = 0.010

Error for 1 bit transmission error.

(c)  How does your answer to part (a) change if each bit is repeated five times (instead of three?

P( m ≤ 2 )

L = Bit (5, 0.94)

   = B (2; 5, 0.94)

   = 0.002

(d)  Imagine a 25 kilobit message (i.e., one requiring 25,000 bits to send). What is the expected number of errors if there is no bit repetition implemented? If each bit is repeated three times?

Given:

h = 25000

Bits are switched during transmission between two computers = 6% = 0.06

m = Bit (25000, 0.06)

E(m) = np

        = 25000 x 0.06

         = 1500

m = Bit (25000, 0.01)

E(m) = 25000 x 0.010

     = 259.2

3 0
3 years ago
7 + 6(w +-6) vbdrufbhjf
ZanzabumX [31]

Answer:

6w - 29

Step-by-step explanation:

8 0
3 years ago
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