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Tomtit [17]
3 years ago
11

Can the following expressions be written in a simpler forms? If yes, write an expression for each problem. If not, explain why w

hy not. exercise 2⁷/4²= 2⁷/2⁴=​
Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

Both of them can be simplified.

Recall that 4 = 2^2.

2^7 / 4^2 = 2^7 / (2^2)^2 = 2^7 / 2^4 = 2^(7-4) = 2^3 = 8

Similarly, 2^7 / 2^4 = 2^(7-4) = 2^3 = 8

The answers to both exercises are 8.

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What do AIA, SAG, AFP and AMA all stand for? Select four options.

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6 0
2 years ago
Need help with this problem, it's got me stuck PLZ
faust18 [17]

24x^2 +25x - 47                     53

----------------------- = -8x -3 - ---------------

ax-2                                     ax-2

add 53/ax-2 to each side

24x^2 +25x - 47+53                    

-----------------------         = -8x -3

ax-2                                    

24x^2 +25x +6                  

-----------------------         = -8x -3

ax-2      

multiply each side by ax-2

24x^2 +25x +6   = (ax-2) (-8x-3)

multiply out the right hand side

24x^2 +25x +6  = -8ax^2 +16x-3ax +6

24 = -8a      25 = 16 -3a

a = -3          9 = -3a

                   a = -3


Choice B

6 0
3 years ago
Evaluate the function.<br> f(x) = 2x2<br> Find f(-3)<br><br> Can anybody answer this?
o-na [289]

Answer:

18

Step-by-step explanation:

f(x) = 2x^2

Let x = -3

f(-3) = 2 * (-3)^2

Exponents first

f(-3)=2 *9

f(3) = 18

6 0
3 years ago
Read 2 more answers
2x²-5x-12=0 (simplify solution set)
Arada [10]

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

ax^2+bx+c=0

Let's find a, b, c:

  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}

x=\frac{5\pm\sqrt{121} }{4}

x=4 or x=\frac{-3}{2}

<u />

<u>Answer:</u>

x = 4 or x = -3/2

7 0
2 years ago
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