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3 years ago

A + 1/a= p find a^3 + 1/a^3(1) p^3 + 3p(2) 3p(3) p^3 - 3p

Mathematics

1 answer:

REY [17]3 years ago

4 0

9514 1404 393

Answer:

(3) p^3 -3p

Step-by-step explanation:

(a +1/a) = p . . . . . . . given

(a +1/a)^3 = p^3 . . . . . . . . cube both sides

a^3 +3a^2(1/a) +3a(1/a)^2 +(1/a)^3 = p^3 . . . . . . expand

(a^3 +1/a^3) +3(a +1/a) = p^3 . . . . . . . . . . simplify, group

(a^3 +1/a^3) +3p = p^3 . . . . . . . . . . substitute p for a+1/a

(a^3 +1/a^3) = p^3 -3p . . . . . . subtract 3p from both sides

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3 years ago

Read 2 more answers

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lutik1710 [3]

Answer:

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Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

$M = 12, \sigma = 124.88$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

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$\sqrt{n} = \frac{205.43}{12}$

$\sqrt{n} = 17.12$

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$n = 293$

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3 years ago

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This is correct, because it takes 27 minutes to get home so it will probably be about 30 minutes.

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3 years ago

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A + 1/a= p find a^3 + 1/a^3(1) p^3 + 3p(2) 3p(3) p^3 - 3p​

A + 1/a= p find a^3 + 1/a^3(1) p^3 + 3p(2) 3p(3) p^3 - 3p