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NNADVOKAT [17]
3 years ago
9

A + 1/a= p find a^3 + 1/a^3(1) p^3 + 3p(2) 3p(3) p^3 - 3p​

Mathematics
1 answer:
REY [17]3 years ago
4 0

9514 1404 393

Answer:

  (3)  p^3 -3p

Step-by-step explanation:

  (a +1/a) = p . . . . . . . given

  (a +1/a)^3 = p^3 . . . . . . . . cube both sides

  a^3 +3a^2(1/a) +3a(1/a)^2 +(1/a)^3 = p^3 . . . . . . expand

  (a^3 +1/a^3) +3(a +1/a) = p^3 . . . . . . . . . . simplify, group

  (a^3 +1/a^3) +3p = p^3 . . . . . . . . . . substitute p for a+1/a

  (a^3 +1/a^3) = p^3 -3p . . . . . . subtract 3p from both sides

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Three times my age in 5 years is 54. How old am i now.
Romashka [77]

Answer:

D. 13

Step-by-step explanation:

54 ÷ 3 = 18 (your age in 5 years)

18 - 5 = 13 (your age now)

8 0
2 years ago
Read 2 more answers
4321342345670<br> +22347968
Ad libitum [116K]

the Answer is

4.3213647e+12

3 0
3 years ago
Complete the table of values
Agata [3.3K]
Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify! 

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, 3^{-2} =&#10;\frac{1}{3^{2} }.
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, (\frac{3}{4}) ^{3}  =  \frac{ 3^{3} }{4^{3} }.
3) The zero exponent rule<span> says that any number raised to zero is 1. For example, 3^{0} = 1.
</span>

Back to the Problem:
Problem 1 
The x-values are in the left column. The title of the right column tells you that the function is y =  4^{-x}. The x-values are:
<span>1) x = 0
</span>Plug this into y = 4^{-x} to find letter a:
y = 4^{-x}\\&#10;y = 4^{-0}\\&#10;y = 4^{0}\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = 4^{-x} to find letter b:
y = 4^{-x}\\ &#10;y = 4^{-2}\\ &#10;y =  \frac{1}{4^{2}} \\  &#10;y= \frac{1}{16}
<span>
3) x = 4
</span>Plug this into y = 4^{-x} to find letter c:
y = 4^{-x}\\ &#10;y = 4^{-4}\\ &#10;y =  \frac{1}{4^{4}} \\  &#10;y= \frac{1}{256}
<span>

Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is y =  (\frac{2}{3})^x. The x-values are:
<span>1) x = 0
</span>Plug this into y = (\frac{2}{3})^x to find letter d:
y = (\frac{2}{3})^x\\&#10;y = (\frac{2}{3})^0\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = (\frac{2}{3})^x to find letter e:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\&#10;y =  \frac{4}{9}
<span>
3) x = 4
</span>Plug this into y = (\frac{2}{3})^x to find letter f:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}
<span>
-------

Answers: 
a = 1
b = </span>\frac{1}{16}<span>
c = </span>\frac{1}{256}
d = 1
e = \frac{4}{9}
f = \frac{16}{81}
5 0
4 years ago
‼️WILL LIST BRAINLIEST ‼️Carlos went to an Astros game. He spent $25.50 each on two tickets, $10.00 for parking, and $27.75 on f
algol13

Answer:

$88.75

Step-by-step explanation:

since he bought two tickets for $25.5 each you have to do 2(25.50) and since he also spent $10 and $27.75 you have to add that as well.

y=2(25.50)+10+27.75

y=51+10+27.75

y=61+27.75

y=88.75

3 0
3 years ago
The median for the given set of six ordered values is 28.5
Alika [10]
X=the missing value

the median is the middle number, but in this case there are two which happens to be 25 and x
so the formula is

25+x/2=31.5
use algebra to solve
25+x=63
x=63-25
x= 38

Therefore, the missing value is 38.

Hope this helped. Let me know if you have any further questions:)
6 0
3 years ago
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