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Vinil7 [7]
3 years ago
13

Can someone help me with #2?? it would be much appreciated! :)

Mathematics
1 answer:
jekas [21]3 years ago
4 0
There you go? Is that right or no?
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If two angles of a triangle are congruent, then the sides opposite those angles are congruent by the converse to the isosceles t
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True they are congruent 
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3 years ago
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Write an equivalent expression for 7(2x - 3y + 6) by modeling and by using the distributive property.
alexandr402 [8]

14x-21y+42 is the answer to this question.

3 0
3 years ago
What are the solutions of the following system x2+y2=25 , 2x+y=-5
tia_tia [17]
Y=5-2x
x^2 + (5-2x)^2 = 25

x^2 + 25-20x+4x^2 = 25

x^2 +4x^2-20x+25=25
5x^2 -20x=0

x=0 and y=5
6 0
2 years ago
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PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!
Nookie1986 [14]

Answer:

\large\boxed{y=\dfrac{1}{4}x^2-x-4}

Step-by-step explanation:

The equation of a parabola in vertex form:

y=a(x-h)^2+k

<em>(h, k)</em><em> - vertex</em>

The focus is

\left(h,\ k+\dfrac{1}{4a}\right)

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of <em>a</em> using k+\dfrac{1}{4a}

<em>k = -5</em>

-5+\dfrac{1}{4a}=-4        <em>add 5 to both sides</em>

\dfrac{1}{4a}=1           <em>multiply both sides by 4</em>

4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4

\dfrac{1}{a}=4\to a=\dfrac{1}{4}

Substitute

a=\dfrac{1}{4},\ h=2,\ k=-5

to the vertex form of an equation of a parabola:

y=\dfrac{1}{4}(x-2)^2-5

The standard form:

y=ax^2+bx+c

Convert using

(a-b)^2=a^2-2ab+b^2

y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5

<em>use the distributive property: a(b+c)=ab+ac</em>

y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4

3 0
3 years ago
The average number of transactions made at an ATM in a 20 minute period is 10. Use an appropriate probability distribution to fi
krek1111 [17]

Answer:

The probability that exactly 6 transactions will be made at an ATM in the next 20 minutes = 0.06306 = 0.0631 to 4d.p

Step-by-step explanation:

This is a Poisson distribution problem

The Poisson distribution formula is given as

P(X = x) = (e^-λ)(λˣ)/x!

where λ = mean = 10 transactions per 20 minutes

x = variable whose probability is required = 6 transactions in the next 20 minutes

P(X = 6) = (e⁻¹⁰)(10⁶)/6! = 0.06306

5 0
3 years ago
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