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Mariana [72]
4 years ago
14

What is 44.5443495 rounded to the nearest hundred thousandths?

Mathematics
1 answer:
Natali5045456 [20]4 years ago
3 0

Answer:

44.54435 is the answer

Step-by-step explanation:      

to get this you look at 44.5443<u>49</u>  then you look at the number behind the <u>4</u> and if it's bigger than 5 the 4 increases by one so it''l be 5, but if the number is less than 5 it stays the same at 4.

hope this helps


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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%20x%20%5E%7B3%7D%20%7D%20" id="TexFormula1" title=" \sqrt{ - x ^{3} } " alt=
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I'm guessing you're given the function y(x)=2-x^3, and you're asked to find the inverse function y^{-1}(x). To do this, swap x and y, then solve for y:

x=2-y^3\implies y^3=2-x\implies y=(2-x)^{1/3}=\sqrt[3]{2-x}

so that the inverse function is

y^{-1}(x)=\sqrt[3]{2-x}

Just to verify:

y(y^{-1}(x))=y(\sqrt[3]{2-x})=2-(\sqrt[3]{2-x})^3=2-(2-x)=x

y^{-1}(y(x))=y^{-1}(2-x^3)=\sqrt[3]{2-(2-x^3)}=\sqrt[3]{x^3}=x

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\sqrt{-x^3}=\sqrt{-x\times x^2}=\sqrt{-x}\sqrt{x^2}

We can simplify this further, but we have to be careful. Suppose x=-1. Then x^2=(-1)^2=1. But we get the same result if x=1, since x^2=1^2=1. There are two possible values of x that given the same value of x^2, so to capture both of them, we take \sqrt{x^2}=|x|, the absolute value of x. Then

\sqrt{-x^3}=|x|\sqrt{-x}

We can't simplify the square root term further than this.

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Answer:

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