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Andreas93 [3]
3 years ago
5

Evaluate the following expression when x = -4 and y = 4. x^6-x/4y

Mathematics
1 answer:
tester [92]3 years ago
4 0

Answer:

Step-by-step explanation:

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Michael pays $30 to enter a state fair, plus $4 for each ride. Which of the following equations represents his total cost? A. y=
omeli [17]
He spends 30 to enter and 4 per ride

y = 4x + 30....with x being the number of rides and y being the total cost
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4 years ago
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<img src="https://tex.z-dn.net/?f=1%2B2x%3D4x%2B9" id="TexFormula1" title="1+2x=4x+9" alt="1+2x=4x+9" align="absmiddle" class="l
kicyunya [14]

Answer:

x= -4

Step-by-step explanation:

=> 1+2x= 4x+9

=> 1-9=4x-2x

=> -8 = 2x

=> x = -8/2

=> x= -4

hope it's helpful to you ☺️

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2/3 * 2/3 divid (2/5 divide 3/5) answer plz
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Answer for Q.1 = 4/9     
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3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
4 years ago
Does anyone know how to get more points in khan academy mastery challenge??
vaieri [72.5K]

Answer:

I would say getting all the them right.

Step-by-step explanation:

There isn't really a way to get more points unless you're getting the questions all correct- So I would say just grind those points!

6 0
2 years ago
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