51/5 is equivalent to 10 and 1/5.
Yes, it is. You may prove it using something like this: 1 is an integer. 1-1 is a difference between integers. A difference between integers returns an integer, so 0 is an integer.
Answer: The base of an equilateral triangle is x + y - 2 = 0 and the opposite vertex is (2, -1). Find the equation of the remaining sides.
Step-by-step explanation:
all u do is divied by 2( -1
Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that 
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
To start off, you can divide the right side of the equation by x to get rid of most of the x's so you get the polynomial x^4 - 10x^2 + 9. This means that f(x) = x^4 - 10x^2 + 9x. By factoring the right side of the equation, you get f(x) = (x^2 - 1)(x^2 - 9). I think the minimum value is 1 and the maximum value is 3.
