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Georgia [21]
2 years ago
6

I have a problem. whats 1+0+2+4x2.

Mathematics
2 answers:
Inga [223]2 years ago
7 0

Answer:

11

Step-by-step explanation:

1) Using the order of operations, you would prioritize the multiplication first:

1 + 0 + 2 + 4 x 2

= 1 + 0 + 2 + 8

2) Then you add:

= 11

IgorC [24]2 years ago
4 0

Answer:

11 is the answer

Step-by-step explanation:

thnxx for the points

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True or false please help it’s due right now
Free_Kalibri [48]

Answer:

false

Step-by-step explanation:

Triangle = 5*6=30/2=15

Parallelogram = 6*5 = 30

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3 years ago
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Simplify :<br> 26-10/2x5+3
zvonat [6]

Answer:

16/13 is the answer.

26-10 is 16 and 2x5+3 is 13

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1. Find the product of 2.6 x 107 and 6.3 x 16
qaws [65]

Answer:

28'042.56

Step-by-step explanation:

2.6 x 107=278.2

6.3 x 16= 100.8

278.2x100.8=28'042.56

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How do you multiply and divide rational expressions?
Citrus2011 [14]

Step-by-step explanation:

Step 1: Factor both the numerator and the denominator.

Step 2: Write as one fraction.

Step 3: Simplify the rational expression.

Step 4: Multiply any remaining factors in the numerator and/or denominator.

Step 1: Factor both the numerator and the denominator.

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8 0
2 years ago
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
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