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3 years ago

6

Jenny spent half of her weekly allowance at the movies. To earn more money her parents leg her clean the gutters for $9. What is

her weekly allowance if she ended with $12? Add an equation and answer.

1 answer:

Kobotan [32]3 years ago

4 0

Answer:

3

Step-by-step explanation:

i think because 12-9=3

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The senior classes at High School A and High School B planned separate

gladu [14]

Answer: Van: 10, Bus: 46

Step-by-step explanation:

Let the number of students in each van be represented by v.

Let the number of students in each bus be represented by b.

The question given can be formed into an equation as:

3v + 13b = 628 ...... i

9v + 2b = 182 ......... ii

Multply equation i by 9

Multiply equation ii by 3

27v + 117b = 5652 ........ iii

27v + 6b = 546 ....... iv

Subtract iv from iii

111b = 5106

b = 5106/111

b = 46

Bus = 46

Recall that 9v + 2b = 182

9v + 2(46) = 182

9v + 92 = 182

9v = 182 - 92

9v = 90

v = 90/9

v = 10

Van = 10

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3 years ago

What is the answer to 9/22 x 11/6

blondinia [14]

<h3>Solution:</h3>

$\frac{9}{22} \times \frac{11}{6} \\ = \frac{3}{2 \times 2} \\ = \frac{3}{4}$

<h3>Answer:</h3>

$\frac{3}{4}$

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3 years ago

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Mila [183]

Step-by-step explanation:

the third option is the right answer

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4 years ago

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Use Theorem 2.1.1 to verify the logical equivalence. Give a reason for each step. -(pv –q) v(-p^q) = ~p

sertanlavr [38]

Answer:

The statement $\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q)$ is equivalent to $\lnot p$ , $\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p$

Step-by-step explanation:

We need to prove that the following statement $\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q)$ is equivalent to $\lnot p$ with the use of Theorem 2.1.1.

So

$\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv$

$\equiv (\lnot p \land \lnot(\lnot q))\lor(\lnot p \land \lnot q)$ by De Morgan's law.

$\equiv (\lnot p \land q)\lor(\lnot p \land \lnot q)$ by the Double negative law

$\equiv \lnot p \land (q \lor \lnot q)$ by the Distributive law

$\equiv \lnot p \land t$ by the Negation law

$\equiv \lnot p$ by Universal bound law

Therefore $\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p$

4 0

3 years ago