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noname [10]
3 years ago
14

Find the area of the figure fast​

Mathematics
2 answers:
Vlada [557]3 years ago
5 0

Answer:

178 m squared

Step-by-step explanation:

pogonyaev3 years ago
3 0
Answer is m^2 because the triangles are 108/2 but there is two so it’ll be 108/2 + 108/2 = 108. Then add that to the rectangle of 5 times 14 which is 70 so final answer is 108 plus 70 which is 178 m^2
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Pair the equivalent fractions.
djverab [1.8K]

Answer:

1. c      2. a     3. b

Step-by-step explanation:

The best way to prove these results are the right ones is by multiplying diagonally :

1.  1/3 = 4/12  -----> 1 . 12 = 12  ; 3 . 4 =12

2.  1/2 = 3/6 ------> 1 . 6 = 6  ;  2 . 3 = 6

3.  2/5 = 6/15 -----> 2 . 15 = 30  ;  5 . 6 = 30

The results of the multiplications must be the same if the fractions are equivalent.

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3 years ago
Please help due in 10 minutes
Shkiper50 [21]

Answer:

I got B or number 2

Step-by-step explanation:

6 0
3 years ago
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Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
find the flux of the constant vector field v→=3i→ 2j→−5k→ through a square plate of area 25 in the xz-plane oriented in the posi
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The flux across a surface is an indicator of the rate at which fluid is flowing through it when there is a fluid flowing in three dimensions and a surface positioned inside that space.

<h3>What is Electric Flux?</h3>
  • A feature of an electric field is electric flux. One way to conceptualize it is as the quantity of forces interacting in a specific space.
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  • A closed surface's field lines are seen as negative when they are directed into it, and as positive when they are directed out of it.
  • Every field line that is directed into a closed surface continues through the interior and is often directed outward somewhere else on the surface if there is no net charge present within the surface.
  • The net, or total, electric flux is zero because the size of the negative and positive fluxes are just about equal.
  • A closed surface that contains a net charge will have a total flux that is proportional to the enclosed charge, positive if it is positive and negative if it is negative.

To Learn more About flux across refer to:

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8 0
1 year ago
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Help me please I need helpp
kvv77 [185]

Answer:

172.8 = 32 x 5.40

Step-by-step explanation:

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