So I'm guessing that the x2 is your way of saying 2 is the exponent right? In that case the equation would be 8x^2 + 12x
Well you would have to pull out the gcf which in this case will be 4x after pulling out the gcf you should get 4x(2x + 3)
Answer:
Many solutions
Step-by-step explanation:
Te x intercepts are where the graph crosses the x axis or wher y=0
the y intercept is where the graph crosses the y axis or where x=0
to find vertex, here is a hack
the x coordinate of the vertex for an equation in form ax^b+bx+c=y is -b/2a
so
y=3x^2+12x+7
-b/2a=-12/2(3)=-12/6=-2
sub that back
y=3(-2)^2+12(-2)+7
y=3(3)-24+7
y=9-17
y=-8
vertex is (-2,-8)
intercepts
x intercept is where y=0
0=3x^2+12x+7
using quadratic formula
x=(-6-√15)/3 and (-6+√15)/3
xints at ((-6-√15)/3,0) and ((-6+√15)/3,0)
yint is where x=0
set x=0
y=7
yint is at y=7 or (0,7)
vertex at (-2,-8)
xints at x=

and

or at the points

and

yint at y=7 or at (7,0)
Problem 1) The triangles are similar because of the AA (angle angle) Similarity Theorem. The first A is the pair of congruent 39 degree angles. The second pair is unmarked, but look at where the triangles meet. They form a pair of vertical angles which are congruent. So we have two pairs of congruent angles allowing us to use the AA Similarity Theorem.
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Problem 2) We can use the SAS (Side Angle Side) Similarity Theorem to prove that these two triangles are similar. The angles are congruent. They are both 29 degrees. So that checks off the "A" portion of SAS. Then notice how the bottom sides are 32 and 64 for the small and large triangle respectively. They form the ratio 32/64 = 1/2, ie the smaller triangle's side is 1/2 as long as the longer counter part. Similarly, 8/16 = 1/2 as well. The ratio is constant at 1/2. This allows us to use the other "S" portions of SAS.
the answer is C) home loan