Part a)
Identify the variable and categoriesBy reading the above statement, we can find that there are two variables and each variable has 2 categories. The variables and their categories are:
1) Class Number
This variable is further divided into 2 categories i.e. Class 9th and Class 10th.
2) Participation in Extracurricular activities
This variable is further divided into 2 categories based on if students participated or not.
Part b)Set up and fill 2 way table.Since, we have 2 variables and each variable has 2 categories the number of data cells will be 2 x 2 = 4 cells
There are total 100 students. 40 students are in class 10th. This means 60 students are in class 9th.Out of 40 students in class 10th, 18 students participate in at least one extracurricular activity. So remaining 22 students do not participate. 32 students from class 9th participate in extracurricular activities, this means the remaining 28 students do not participate. Based on this data, we can fill up the table as shown below
Answer:
x=-2
Step-by-step explanation:
(2/3)^x-1=27/8
Rewriting the right hand side
(2/3)^x-1=(3/2)^3
We know that a^-b = 1/a^b Hint: { 1/(3/2) = 2/3}
(2/3)^x-1=(2/3) ^-3
The bases are the same, so the exponents are the same
x-1 = -3
x -1+1 = -3+1
x = -2
50ft x 40ft x 0.5ft = 1,000 ft³ of soil needed for the project
1000/3= 333.3 bags of soil would be needed, so round up to 334.
334 x $2.25 = $751.50
convert the feet³ to yards³, divide the 1000 ft³ by 27 (27 ft³ in 1 yard³)
1000/27= 37.037(repeating) yd³ I'll round up to 38 yd³
38yd³ x $18 = $684 + $50 delivery fee = $734
So, the bulk soil is less expensive by $17.50
First, figure out its slope. that is (4-2)/(2-1)=2
then, write its point-slope form:
y-(-3)=2(x-2)