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Answer:
Dimensions of section B = 36 inches, 48 inches
Area of the piece of sheet metal after both sections are cut and removed = 6336 square inches
Step-by-step explanation:
Given: Width and length of a rectangular piece of sheet metal are 60 inches and 44 inches.
To find: dimensions of section B, the area of the piece of sheet metal after both sections are cut and removed
Solution:
Length of rectangle B = TR = SR - ST = PQ - ST (As SR = PQ being opposite sides of rectangle)
Length of rectangle B = PQ - ST = 60 - 24 = 36 inches
Breadth of rectangle B = UR = QR - QV - VT - TU
Here, QR = PS = 144 inches (opposite sides of rectangle PQRS are equal )
QV = 36 inches
VT = WX = 24 inches ( opposite sides of rectangle WVTX are equal)
TU = 36 inches
So,
Breadth of rectangle B = 144 - 36 - 24 - 36 = 48 inches
Area of rectangle B = length × breadth = 36 × 48 = 1728 square inches
Area of rectangle WVTX = length × breadth = 24 × 24 = 576 square inches
Area of rectangle PQRS = PQ × PS = 60 × 144 = 8640 square inches
Area of the piece of sheet metal after both sections are cut and removed =8640 - ( 1728 + 576 ) = 8640 - 2304 = 6336 square inches
