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2 years ago

NEED HELP ASAP

Mathematics

1 answer:

AleksandrR [38]2 years ago

6 0

Answer:

times 3

Step-by-step explanation:

add 8 and plus the 10

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What do I do for this problem

slamgirl [31]

To divide fractions, you need to multiply by the reciprocal. The reciprocal of 3/4 is 4/3, which is why the work is incorrect.

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3 years ago

Which measurements are equal to 671 decimeters? Check all that apply.

Shtirlitz [24]

1, 4, and 5:) hope this helps.

3 0

2 years ago

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kkurt [141]

Answer:

90+1,2 = 200

Step-by-step explanation:

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6 0

2 years ago

The number of traffic accidents per day on a certain section of highway is thought to be Poisson distributed with a mean equal 2

stich3 [128]

Answer:option B is the correct answer

Step-by-step explanation:

The formula for poisson distribution is expressed as

P(x = r) = (e^- µ × µ^r)/r!

Where

µ represents the mean of the theoretical distribution.

r represents the number of successes of the event.

From the information given,

µ = 2.19

For the probability of no accidents on this section of highway during one day period, r = 0

Therefore,

P(x = 0) = (e^- 2.19 × 2.19^0)/0!

P(x = 0) = (e^- 2.19 × 1)/1

P(x = 0) = 0.112

4 0

3 years ago

Hi there,<br> I need help to solve the perimeter and the surface area of this shape.<br> Thanks!

leonid [27]

Answer: Perimeter = 6π ≈ 18.84

Area = 15π ≈ 47.10

<u>Step-by-step explanation:</u>

This is a composite of a big semicircle with diameter of 10 --> radius (r) = 5

plus a medium semicircle with diameter of 6 --> r = 3

minus a small semicircle with diameter of 4 --> r = 2

Perimeter of a semicircle = $\dfrac{1}{2}(2\pi r)=\pi r$

$P_{big}=\pi (5)\quad =5\pi\\P_{medium}=\pi (3)\quad =3\pi\\P_{small}=\pi (2)\quad =2\pi\\P_{composite} =5\pi+3\pi -2\pi\\.\qquad \qquad =\large\boxed{6\pi}$

Area of a semicircle = $\dfrac{1}{2}(\pi r^2)$

$A_{big}=\dfrac{1}{2}\pi (5)^2\quad =12.5\pi\\\\A_{medium}=\dfrac{1}{2}\pi (3)^2\quad =4.5\pi\\\\A_{small}=\dfrac{1}{2}\pi (2)^2\quad =2\pi\\\\A_{composite} =12.5\pi+4.5\pi -2\pi\\\\.\qquad \qquad =\large\boxed{15\pi}$

8 0

3 years ago