<h3> Answer:</h3><h2>a.215</h2>
I don't know in letter b.
#CaRRyOnLeArniNG
Answer:
Step-by-step explanation:
given data;
B = 16m
b =8 m
height H = 4 m
length L = 32 m
volume of any right cylinder = (Area of bottom) \times (length)
Volume = A* L
The area of a trapezoid is
therefore volume is given as
volume = 48*32
let's firstly convert both fractions with the same denominator, by simply <u>multiplying each fraction by the other's denominator</u>, let's proceed.
![\bf -\cfrac{3}{4}\cdot \cfrac{3}{3}\implies \boxed{-\cfrac{9}{12}}~\hfill -\cfrac{1}{3}\cdot \cfrac{4}{4}\implies \boxed{-\cfrac{4}{12}} \\\\[-0.35em] ~\dotfill\\\\ \boxed{-\cfrac{9}{12}}~~,~~\stackrel{-\frac{2}{3}}{-\cfrac{8}{12}}~~,~~-\cfrac{7}{12}~~,~~\stackrel{-\frac{1}{2}}{-\cfrac{6}{12}}~~,~~-\cfrac{5}{12}~~,~~\boxed{-\cfrac{4}{12}}](https://tex.z-dn.net/?f=%5Cbf%20-%5Ccfrac%7B3%7D%7B4%7D%5Ccdot%20%5Ccfrac%7B3%7D%7B3%7D%5Cimplies%20%5Cboxed%7B-%5Ccfrac%7B9%7D%7B12%7D%7D~%5Chfill%20-%5Ccfrac%7B1%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B4%7D%5Cimplies%20%5Cboxed%7B-%5Ccfrac%7B4%7D%7B12%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cboxed%7B-%5Ccfrac%7B9%7D%7B12%7D%7D~~%2C~~%5Cstackrel%7B-%5Cfrac%7B2%7D%7B3%7D%7D%7B-%5Ccfrac%7B8%7D%7B12%7D%7D~~%2C~~-%5Ccfrac%7B7%7D%7B12%7D~~%2C~~%5Cstackrel%7B-%5Cfrac%7B1%7D%7B2%7D%7D%7B-%5Ccfrac%7B6%7D%7B12%7D%7D~~%2C~~-%5Ccfrac%7B5%7D%7B12%7D~~%2C~~%5Cboxed%7B-%5Ccfrac%7B4%7D%7B12%7D%7D)
Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
Answer:
third side is 4
Step-by-step explanation:
using Pythagoras theorem,
(√33)² + l² = 7²
33 + l² = 49
l² = 49 - 33
l² = 16
l = √16
l = 4
