All categories

3 years ago

JKL is a straight line.

Mathematics

1 answer:

kirza4 [7]3 years ago

3 0

Answer:

x = 32°

Step-by-step explanation:

∆KLM is an isosceles triangle because it has two equal sides, KL & KM. Therefore, the angles opposite to each of the two equal sides, which are referred to as the base angles are congruent to each other.

m<KML = m<KLM = 58°

m<MKL = 180 - (58 + 58) (Sum of triangle)

m<MKL = 64°

m<JKM = 180 - m<MKL (linear pair theorem)

m<JKM = 180 - 64 (Substitution)

m<JKM = 116°

∆JKM is also an isosceles triangle with two equal sides. Therefore, it's based angles (x & <J) would also be equal to each other.

Thus:

x = ½(180 - m<JKM)

x = ½(180 - 116) (Substitution)

x = 32°

You might be interested in

Question 7 of 10

Anna [14]

Answer:

C. a combination of wage or salary other types of compensation

Step-by-step explanation:

A compensation package is synopsis/summary of all the ways a company can pay its employees. It can be indirectly or directly.

3 0

3 years ago

Solve using any method of substitution<br><br>x = 4y + 14<br>y = -3 + 3

leonid [27]

X=18y
Y=0

Hope this helps :)

8 0

3 years ago

HELP ASAP PLEASE 10 POINTS!

UkoKoshka [18]

I think the answer would be c

5 0

3 years ago

What is the value of the discriminant for the quadratic equation 0=x+2+x^2

boyakko [2]

$D=b^2-4ac\\a=1, b=1, c=2\\D=1^2-4×1×2=-7$

4 0

3 years ago

Brainliest to first correct answer

Artyom0805 [142]

Answer:

Smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

Step-by-step explanation:

We need to find the surface area of all cuboids.

Surface Area of Cuboid A:

Length = 6

Breadth = 25

Height = 4

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((6 \times 25)+(25 \times 4)+(6 \times 4))\\Surface \ Area \ of \ Cuboid=2(150+100+24)\\Surface \ Area \ of \ Cuboid=2(274)\\Surface \ Area \ of \ Cuboid=548\: cm^2$

So, Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B:

Length = 10

Breadth = 6

Height = 10

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2(10 \times 6)+(6 \times 10)+(10 \times 10))\\Surface \ Area \ of \ Cuboid=2(60+60+100)\\Surface \ Area \ of \ Cuboid=2(220)\\Surface \ Area \ of \ Cuboid=440\: cm^2$

So, Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C:

Length = 2

Breadth = 20

Height = 15

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((2 \times 20)+(20 \times 15)+(2 \times 15))\\Surface \ Area \ of \ Cuboid=2(40+300+30)\\Surface \ Area \ of \ Cuboid=2(370)\\Surface \ Area \ of \ Cuboid=740\: cm^2$

So, Surface Area of Cuboid C = 740 cm²

So, We get:

Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C = 740 cm²

The company wants to choose the design having smallest surface area.

So, smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

5 0

3 years ago