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masya89 [10]
3 years ago
13

Write the six step in division

Mathematics
1 answer:
joja [24]3 years ago
5 0

Answer:

Divide the tens column dividend by the divisor. Multiply the divisor by the quotient in the tens place column. Subtract the product from the divisor

Step-by-step explanation:

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Archy [21]

In terms of pi means to include pi in your answer. In other words, don't use 3.14 or 22/7 for pi.

8 0
3 years ago
Write an equation of the line in slope-intercept form: y-intercept of 2, x-intercept of 4
zvonat [6]

Answer:

\sf y=-\dfrac12x+2

Step-by-step explanation:

y-intercept is when x = 0, so (0, 2)

x-intercept is when y = 0, so (4, 0)

\sf slope=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{0-2}{4-0}=-\dfrac12

Slope-intercept form of linear equation:  \sf y=mx+b

(where m is the slope and b is the y-intercept)

Given:

  • \sf m=-\dfrac12
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\sf \implies y=-\dfrac12x+2

3 0
2 years ago
Which is the equivalent of 12.42 written in DMS form?
nika2105 [10]
12.42

12°+.42(60)

12°25.2'

12°25'+.2(60)

12°25'12"
3 0
3 years ago
Read 2 more answers
What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3 ?
Svet_ta [14]

<u>Answer</u>

y = -2x + 10


<u>Explanation</u>

The general equation for a straight line is y = mx + c where m and c are gradient and y-intercept respectively.

y=x/2+3 = y (1/2)x + 3

gradient = 1/2

Gradient of the line perpendicular to y=x/2+3 is;

m × 1/2 = -1

m = -2

Now we find the equation of a line passing through (1,8) and have a gradient of -2.

-2 = (y - 8)/(x - 1)

-2(x - 1) = (y - 8)

2 -2x = y - 8

y = -2x + 10


3 0
3 years ago
Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation x2 + 4x + 8 = 0. Which e
levacccp [35]
C because b^2 - 4ac is less than 0.
4 0
3 years ago
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