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kolezko [41]
3 years ago
10

Fill in the blank: 65 + ______ - 15 = 65

Mathematics
2 answers:
katrin2010 [14]3 years ago
7 0

Answer:

15

Step-by-step explanation:

65+15-15=65

SIZIF [17.4K]3 years ago
4 0

Answer:

65+15-15=65 can be the answer!!

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5xy —9cs (-)-3xy + cs simplify
aalyn [17]

Answer:

Step-by-step explanation:

2 • (xy - 4cs)

7 0
4 years ago
5 min 0 sec minus 35 sec
nata0808 [166]
4 minutes and 25 seconds
5 0
4 years ago
The amount of time Jill trained for a marathon this month is​ 125% of the amount of time she trained last month. Jill trained fo
Liono4ka [1.6K]

Answer:

Step-by-step explenation . First you know that the amount of time she trained for the marathon is 125% of the time she trained last month. We also know that she trained 80 hours last month.  And the question wants us to know how many hours she trained this month.  So we do 100% =x

And 125% = 80 so we cross multiply it becomes 100 X 80 =125x witch eaquals to 8,000 divided by  125 witch is 64. So the final Answer is 64 . IF I AM CORRECT PLEASE MARK BRAINLIEST.

7 0
3 years ago
Can someone please help m by giving a yes or no answer
aleksklad [387]

Answer:

Yes

Step-by-step explanation:

a function would be a constant negative and a positive relationship, which is present in this picture.

6 0
3 years ago
the radius of the inner white circle of the doughnut is 2cm. The circumference of the outer edge of the doughnut is 43.96cm. Wha
Elenna [48]

Answer:

141.4 sq cm

Step-by-step explanation:

to find the area of the outer circle with a smaller circle inscribed within, you find the area of each and subtract the smaller area from the larger

the radius of the smaller circle is 2

we have to find the radius of the larger circle so we use what we know about its circumference:

C = 2πr

43.96 = 2πr

21.98 = πr

21.98 / π = r

r ≈ 7 cm

now use r = 7 to find area of larger circle:

A = πr²

A = π49

Area of smaller circle:  4π

Area of larger circle without including inner section is 49π - 4π = 45π

45π ≈ 141.4 sq cm

7 0
3 years ago
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