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Find the mean,median,mode and range for each set of data its 23,27,24,26,26,24,26,24

lilavasa [31]

Mean is the average of the data set, which is found by adding all values together and then dividing that sum by the number of data values.

Median is the middle number of the data set, and can be found by ordering the values from least to greatest. If there are two middle numbers, the average of the two would be the median.

Mode is the number that shows up most frequently in the data set.

Range is found by subtracting the lowest number from the highest number in the data set.

Set 1

Mean:

18+20+22+11+19+18+18=126

126÷7=18

Median:

11, 18, 18, 18, 19, 20, 22 → 18

Mode: 18

Range: 22-11=11

Set 2

Mean: 23+27+24+26+26+24+26+24=200

200÷8=25

Median:

23, 24, 24, 24, 26, 26, 26, 27 → 24+26=50 → 50÷2=25

Mode: 24 and 26

Range: 27-23=4

4 0

3 years ago

Read 2 more answers

A company offers four plans for customers who want to rent DVDs and video games. The cost of the plans can be modeled by a linea

Luba_88 [7]

To solve this, we are going to use the slope formula, and the point slope formula.
Slope formula: $m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
where
$m$ is the slope.
$(x_{1},y_{1})$ are the coordinates of the first point.
$(x_{2},y_{2})$ are the coordinates of the first point.
Point-slope formula: $y-y_{1}=m(x-x_{1})$

Plan A. Coordinates of the first point: (1,14) (number of discs, cost). Coordinates of the second point: (2,17). Lets replace those values in our slope formula:
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{17-14}{2-1}$
$m=3$
Now that we have the slope, we can use the point slope formula:
$y-y_{1}=m(x-x_{1})$
$y-14=3(x-1)$
$y-14=3x-3$
$y=3x+11$
Remember that in a linear equation of the form $y=mx+b$ , $m$ is the slope and $b$ is the y-intercept. In our model the y-intercept is the membership fee.
Since $b=11$ in our linear equation, we can conclude that the membership fee is $11

Plan B. Coordinates of the first point (1,12). Coordinates of the second point (2,16).
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{16-12}{2-1}$
$m=4$
$y-y_{1}=m(x-x_{1})$
$y-12=4(x-1)$
$y-12=4x-4$
$y=4x+8$
Membership fee: $8

Plan C. Coordinates of the first point: (1,10). Coordinates of the second point: (2,15).
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{15-10}{2-1}$
$m=5$
$y-y_{1}=m(x-x_{1})$
$y-10=5(x-1)$
$y-10=5x-5$
$y=5x+5$
Membership fee: $5

Part D. Coordinates of the first point: (1,12). Coordinates of the second point (2,21).
$m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \frac{21-12}{2-1}$
$m=9$
$y-y_{1}=m(x-x_{1})$
$y-12=9(x-1)$
$y-12=9x-9$
$y=9x+3$
Membership fee: $3

We can conclude that the plan that has the smallest one-time membership is Plan D.

6 0

3 years ago

Read 2 more answers

Please I really need help on these two

oksian1 [2.3K]

Answer:

1) 5

2) (3 , 24)

Step-by-step explanation:

Question 1

f(x) x= 1 2 * 5¹ = 10

f(x) x= 2 2 * 5² = 50

f(x) x= 3 2 * 5³ = 250

multiplicative rate of change = 50/10 = 5

check: 250/50 = 5

Question 2

f(x) = 2 * 4ˣ

(3 , 24) f(3) = 2 * 4³ = 2 * 64 = 128 ≠ 24

3 0

3 years ago

What is the solution to the system please help

IrinaVladis [17]

Answer:

$(-\frac{50}{13},-\frac{12}{13})$

Step-by-step explanation:

To start, you need to find the equation of both of these lines. For the orange one, the slope can be found with the points (-5,0) and (0,-4), where there is a drop of 4 for a run of 5. This is a slope of -4/5, and a y-intercept of -4. For the purple line, you can use the points (-2,0) and (0,1), where there is a rise of 1 for a run of 2 or a slope of 1/2 and a y intercept of 1. Therefore, the two equations are:

$y=-\frac{4}{5}x-4$