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3 years ago

6

First person to reply gets brainliest

1 answer:

aniked [119]3 years ago

6 0

Answer:

I'm not first, but thanks for the points! Have a nice day! :D

Step-by-step explanation:

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I Only Need #9 Not 10

Minchanka [31]

Answer:

6

Step-by-step explanation:

Remember the last question? to find circumference you have to multiply the diameter by 3.14? well same here except you divide the circumference by 3.14 to get the diameter. so divide 18.84 ÷ 3.14 = 6

~R3V0

$d= \frac{C}{\pi }$

$C = \pi d$ (pi times d)

5 0

3 years ago

Erica earns $10.50 an hour for the first 40 hours. She is paid time and a half for every hour worked over 40 hours during a week

hjlf

Answer:

Step-by-step explanation:

10.50 X 40=420

55-40=15

15 X 2=30

15 divided by = 7.50

420+30+7.5= 450.5

5 0

3 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago

Is A ABC similar to DEF? Why or why not?

vova2212 [387]

Answer:

Option(D)

Step-by-step explanation:

Given are the two triangles, that are ABC and DEF, in which AB=8ft, DE=6ft, AC=10ft and DF=7.5ft.

For the two triangles to be similar, it must satisfy the similarity condition that is:

Both the triangles must have congruent angles and the sides should be proportional. Since, two sides of the given triangles are not proportional.Moreover, ∠A=25° and ∠D=24° which are not equal and ∠C=60° and ∠F=61° which are also not equal.

Therefore, Not all the angles are congruent, thus the triangles cannot be similar.

6 0

3 years ago

Read 2 more answers

Which equation is quadratic in form?

just olya [345]

Answer:

2

Step-by-step explanation:

i think

5 0

3 years ago

Read 2 more answers