Csc a - sin a = cos a cot a
1/sin a - sin a = cos a (cos a / sin a)
(1 - sin^2 a)/sin a = cos^2 a/sin a
cos^2 a/sin a = cos^2 a/sin a
Therefore, the given equation is an identity.
Answer:
Option 3 or Option 4.
Step-by-step explanation:
I have this doubt because actually, a rhombus with a right angle (one) is not necessarily a square. Some rhombuses have one right angle and are still not squares. Now, if the four angles are right, it is a square, but this only says one.
On other hand, a parallelogram with congruent diagonals isn't a square necessarily either. Rectangles have congruent diagonals and are parallelograms.
In case you only can answer with one, I'll say is option 3, hope it helps!
Answer:
i dont get it
Step-by-step explanation:
Answer:
x = 12
Step-by-step explanation:
Step 1: Define
f(x) = 4x + 6
f(x) = 54
Step 2: Substitute variables
54 = 4x + 6
Step 3: Solve for <em>x</em>
<u>Subtract 6 on both sides:</u> 48 = 4x
<u>Divide both sides by 4:</u> 12 = x
Step 4: Check
<em>Plug in x to verify it is a solution.</em>
f(12) = 4(12) + 6
f(12) = 48 + 6
f(12) = 54
