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ELEN [110]
3 years ago
6

Find the mean,median,mode and range for each set of data its 23,27,24,26,26,24,26,24

Mathematics
2 answers:
emmasim [6.3K]3 years ago
8 0

Answer:

23, 24, 24, 24, 26, 26, 26, 27

Median: 25

Mode: 24 and 26

Mean: 23 + 24 + 24 + 24 + 26 + 26 + 26 + 27 = 200/8 = 25

lilavasa [31]3 years ago
4 0

Mean is the average of the data set, which is found by adding all values together and then dividing that sum by the number of data values.

Median is the middle number of the data set, and can be found by ordering the values from least to greatest. If there are two middle numbers, the average of the two would be the median.

Mode is the number that shows up most frequently in the data set.

Range is found by subtracting the lowest number from the highest number in the data set.

<u>Set 1</u>

Mean:

18+20+22+11+19+18+18=126

126÷7=18

Median:

11, 18, 18, 18, 19, 20, 22 →  18

Mode: 18

Range: 22-11=11

<u>Set 2</u>

Mean: 23+27+24+26+26+24+26+24=200

200÷8=25

Median:

23, 24, 24, 24, 26, 26, 26, 27 → 24+26=50 → 50÷2=25

Mode: 24 and 26

Range: 27-23=4

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Use the discriminant to describe the roots of each equation. Then select the best description. 2m2 + 3 = m double root real and
Jlenok [28]

Answer:

The roots of the equation 2m²+3=m are non-real roots.

Step-by-step explanation:

Given equation:

2m²+3=m

2m²-m+3=0

Here, from the equation we can obtain the following values:

a = 2, b = -1, c = 3

Discriminant of an equation is given as:

D = b²-4ac

= (-1)²-4(2)(3)

= 1 - 21

= -20

Discriminant can tell what kinds of roots the equation have.

In our case, the discriminant is less than 0.

When D < 0, the roots of the equation are complex conjugates.(non-real)

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I need help finding the circumference of F
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3 years ago
Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
  • y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

  • (x₁, y₁) = coordinates of end of diameter = (12, 3) and
  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

5 0
2 years ago
Find the length indicated.
erica [24]
Option B. 8

7+3 = 10
18-10 = 8
8 0
2 years ago
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