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Gwar [14]
3 years ago
5

What is 60 x blank = 300?

Mathematics
2 answers:
gulaghasi [49]3 years ago
8 0

Answer:

60 multiplied by 5 gives 300..

Step-by-step explanation:

Temka [501]3 years ago
7 0

Answer:

5

Step-by-step explanation:

300/60=5

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Select the best answer for the question
artcher [175]

Answer:

C

HOWEVER: "Less Than" is usually depicted as a dashed line at the border. and there MUST be an OR between these two equations to include all of the blue area. An "and" there would exclude the area between the edge lines.

Step-by-step explanation:

2x + y < 10

       y < -2x + 10

3x + 2y < 12

       2y < -3x + 12

         y < -1.5x + 6

3 0
3 years ago
Bills car gets 30 miles to the go on. For every galon of gas it consumes his car runs 30 miles use this information to determine
jok3333 [9.3K]

Answer:

60

Step-by-step explanation:

30+30=60

5 0
3 years ago
A storekeeper increased the price of hats by 8% A hat was originally priced at $12.00. What is the new cost of the hat?
german

Answer:

$12.96

Step-by-step explanation:

determine what the decimal form of 8% is

⇒ 8% = 0.08

multiply $12 by 0.08

⇒ $12 x 0.08

⇒ $0.96

add $0.96 to $12

⇒ $12 + $0.96

⇒ $12.96

new price

⇒ $12.96

6 0
3 years ago
What is 3x+X short answer
nikdorinn [45]

4x................... I hope it helps

8 0
3 years ago
Suppose that X is a subset of Y. Let p be the proposition ‘x is an element ofX’ and let q be the proposition ‘x is an element of
Genrish500 [490]

Answer:

See answer below

Step-by-step explanation:

The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.

i) x∈AnB  if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB  then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.

ii) (I will abbreviate "if and only if" as "iff")

x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.

iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).

iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).

8 0
3 years ago
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