Answer:
One approach would be to move all items from stack1 to stack2 (effectively reversing the items), then pop the top item from stack2 and then put them back.
Assume you use stack1 for enqueueing. So enqueue(x) = stack1.push(x).
Dequeueing would be:
- For all items in stack1: pop them from stack1 and push them in stack 2.
- Pop one item from stack2, which will be your dequeue result
- For all items in stack2: pop them from stack2 and push them in stack 1.
Hope it makes sense. I'm sure you can draw a diagram.
Celebrating influences food in more than 1 way
The additional elements needed of a network architecture are:
- Policy management
- Remote access server
- VPN Gateway, etc.
<h3>What is network architecture example?</h3>
Network architecture is known to be the set up of a computer network. It is regarded as the backbone for the specification of the physical attributes of a network and also their functional configuration.
An examples is a printer that is linked to the network. Note that additional elements required of a network architecture if the enclave is to support remote access through the public Internet are Policy management, etc.
Learn more about network architecture from
brainly.com/question/13986781
Answer:
Selection control structure
Explanation:
This is often referred to as if-conditional statement;
This condition tests for a condition and performs a sequence of operation depending on the result of the condition;
Take for instance, the following program written in python
<em>x = int(input("enter any number: "))</em>
<em>if x < 0:</em>
<em> print("Yes")</em>
<em>else</em>
<em> print("No")</em>
<em />
The above checks if the input number is less than 0,
If the condition is true, it prints Yes
If otherwise, it prints No
<span>'m pretty sure the big O is actually O(log n)
Not really a proof but anyway.
If you write out the values before each iteration of the loop you get.
L - iteration number
L i t
1 1 0
2 1 2
3 3 6
4 9 18
5 27 54
6 81 162
So if n was 80 it would take 6 iterations
You can see i is growing like 3^(L-2)
So if n was 1000
1000 = 3^(L-2)
log(1000) [base 3] = L - 2
log(1000) [base 3] + 2 = L
8.287709822868152 = L
and if you ceil the answer you get L = 9
and just to check with the table
6 81 162
7 243 486
8 729 1458
9 2187 ...
The table isn't perfect but hopefully you get the main idea.</span>
