Hello there, this problem is just basic addition, here is what it would look like
Solve it and we get 78.21
What is the depth of the soup ( the area shaded) 20cm is the diameter?
1 answer:
Answer:
8 cm
Step-by-step explanation:
Given that , the diameter of the semicircle is 20 cm . And the angle made by the level of liquid and the diameter is 37°. For diagram kindly refer to attachment .Let the depth of the liquid be represented by h . Now from the figure , ( attached ) :-
⇒ cos 37° = AB / AC
⇒ cos 37° = AB / 20 cm
⇒ 4/5 = AB / 20 cm .
⇒ AB = 4/5 * 20 cm .
⇒ AB = 16 cm .
Now , again AOB is s semicircle and AB is diameter , And the radius will be half of diameter .Hence here h = r = 16cm/2 = 8 cm .
<h3><u>Hence</u><u> </u><u>the</u><u> </u><u>depth</u><u> </u><u>of</u><u> </u><u>the </u><u>soup</u><u> </u><u>is</u><u> </u><u>8</u><u> </u><u>cm</u><u> </u><u>.</u></h3>
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------------------------------------------------------------------
Equation
------------------------------------------------------------------
x² + 4x = 0
------------------------------------------------------------------
Add a constant
------------------------------------------------------------------
x² + 4x + (4/2)² - (4/2)² = 0 ← Add 2² to form perfect square
------------------------------------------------------------------
Evaluate bracket
------------------------------------------------------------------
x² + 4x + 2² - 2² = 0
------------------------------------------------------------------
Form the perfect square
------------------------------------------------------------------
(x + 2)² = 4
------------------------------------------------------------------
Square root both sides
------------------------------------------------------------------
(x+2) =
√4
------------------------------------------------------------------
Evaluate the square root
------------------------------------------------------------------
(x+2) = 2
------------------------------------------------------------------
Solve x
------------------------------------------------------------------
x = 2 - 2 or x = -2 - 2
x = 0 or -4
------------------------------------------------------------------
Answer: The constant to add is 4 and the value of x = 0 or -4
------------------------------------------------------------------
Equation
------------------------------------------------------------------
x² + 4x = 0
------------------------------------------------------------------
Add a constant
------------------------------------------------------------------
x² + 4x + (4/2)² - (4/2)² = 0 ← Add 2² to form perfect square
------------------------------------------------------------------
Evaluate bracket
------------------------------------------------------------------
x² + 4x + 2² - 2² = 0
------------------------------------------------------------------
Form the perfect square
------------------------------------------------------------------
(x + 2)² = 4
------------------------------------------------------------------
Square root both sides
------------------------------------------------------------------
(x+2) =
------------------------------------------------------------------
Evaluate the square root
------------------------------------------------------------------
(x+2) =
------------------------------------------------------------------
Solve x
------------------------------------------------------------------
x = 2 - 2 or x = -2 - 2
x = 0 or -4
------------------------------------------------------------------
Answer: The constant to add is 4 and the value of x = 0 or -4
------------------------------------------------------------------