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Andreas93 [3]
3 years ago
14

Work out the following (+35) + (-33)

Mathematics
2 answers:
musickatia [10]3 years ago
3 0

Answer:

2

Step-by-step explanation:

so (+35) can be written as 35 because it's automatically already positive. +(-33) can be written as -33 because of one negative sign and one positive sign (if it was two negative or two positive, it would be positive). it's the same as 35-33, and 35-33=2.

Nataliya [291]3 years ago
3 0

Answer:

(+35) + (-33)

⇒ 35-33

⇒2

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Post war means the time after a war had just taken place
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How much sand would you need to fill this box ?
grin007 [14]

Step-by-step explanation:

We have,

l =5ft

b=2ft

h=3ft

volume(v) = l \times b \times h

v = (l*b*h)

v = (5*2*3)ft

v = (30)ft

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3 0
3 years ago
carlos and Jacob each improve their yards by planting daylilies and ivy. They bought their supplies from the same stores. Carlos
34kurt

Answer:

Cost of each daylilies = $3

Cost of each ivy pot = $3

Step-by-step explanation:

Given:

Cost of 4 daylilies and 4 ivy = $24

Cost of 4 daylilies and 8 ivy = $36

Find:

Cost of each daylilies

Cost of each ivy pot

Computation:

Assume;

Cost of each daylilies = a

Cost of each ivy pot = b

So,

4a + 4b = 24....... eq 1

4a + 8b = 36 ....... eq 2

Eq2 - Eq1

8b - 4b = 36 - 24

4b = 12

b = 3

So,

Cost of each ivy pot = $3

4a + 4b = 24

4a + 4(3) = 24

4a + 12

a = 3

Cost of each daylilies = $3

6 0
3 years ago
chris bought a cup of hot chocolate does his cup probably hold 400 liters or 400 milliliters of hot chocolate
vivado [14]

Answer:

Millileters

Step-by-step explanation:

If it held 400 liters, it would be a pretty gigantic cup

8 0
3 years ago
Read 2 more answers
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
Read 2 more answers
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