Post war means the time after a war had just taken place
Step-by-step explanation:
We have,
l =5ft
b=2ft
h=3ft

v = (l*b*h)
v = (5*2*3)ft
v = (30)ft
.•. v = 30ft
Answer:
Cost of each daylilies = $3
Cost of each ivy pot = $3
Step-by-step explanation:
Given:
Cost of 4 daylilies and 4 ivy = $24
Cost of 4 daylilies and 8 ivy = $36
Find:
Cost of each daylilies
Cost of each ivy pot
Computation:
Assume;
Cost of each daylilies = a
Cost of each ivy pot = b
So,
4a + 4b = 24....... eq 1
4a + 8b = 36 ....... eq 2
Eq2 - Eq1
8b - 4b = 36 - 24
4b = 12
b = 3
So,
Cost of each ivy pot = $3
4a + 4b = 24
4a + 4(3) = 24
4a + 12
a = 3
Cost of each daylilies = $3
Answer:
Millileters
Step-by-step explanation:
If it held 400 liters, it would be a pretty gigantic cup
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0
As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81
Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2
So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2
A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.
3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.
So 2k^2 = 9 + 3k have two rational solutions (Option B).
Hope this Helps! :)