Given that grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height.
So if D is the diameter and h is the height of the conical pile then we can write:
D=3h
We know that diameter = 2r, where r is the radius
2r=3h

Volume of conical pile is given by formula

Given that volume is 1110 cubic feet.
Now plug the values of Volume and r into equation of volume





take cube root of both sides
7.78103342467=h
Hence height is approx 7.78 feet.
<u>Given</u>:
The sides of the base of the triangle are 8, 15 and 17.
The height of the prism is 15 units.
We need to determine the volume of the right triangular prism.
<u>Area of the base of the triangle:</u>
The area of the base of the triangle can be determined using the Heron's formula.

Substituting a = 8, b = 15 and c = 17. Thus, we have;


Using Heron's formula, we have;





Thus, the area of the base of the right triangular prism is 36 square units.
<u>Volume of the right triangular prism:</u>
The volume of the right triangular prism can be determined using the formula,

where
is the area of the base of the prism and h is the height of the prism.
Substituting the values, we have;


Thus, the volume of the right triangular prism is 450 cubic units.
Answer:
x=20; vertical angles theorem
Step-by-step explanation:
hi! we can use the vertical angles theorem for this. vertical angles are congruent to each other, meaning they are the same amount of degrees. so, we can set 2x+10 and 50 equal to each other.
2x+10=50
2x=40
x=20
x=20 because of the vertical angles theorem.
Multiply the dimensions to get 174,720 in^3
<h2>
Answer:</h2>
The values of x for which the given vectors are basis for R³ is:

<h2>
Step-by-step explanation:</h2>
We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.
We are given three vectors as:
(-1,0,-1), (2,1,2), (1,1, x)
The matrix formed by these vectors is:
![\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%262%261%5C%5C0%261%261%5C%5C-1%262%26x%5Cend%7Barray%7D%5Cright%5D)
Now, the determinant of this matrix is:

Hence,
