2x^2y(y^3-5)+14(y^3-5)
(2x^2y)+14(y^3-5)
2(x^2y+7)(y^3-5)
x^2y+7 Is a factor
H(t)=-16t²+160
0=-16t²+160
16t²=160
t²=10
t=√10 or 3.16 seconds
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Answer:
8x + 4 - z
Step-by-step explanation:
Given the following :
The distance from her house to school is 2x+5 The distance from the school to the park is z If the total distance she was that day is 10x +9 how far is it from the park back to her
Distance from house to school = 2x + 5
Distance from school to park = z
Total distance covered = 10x + 9
Distance from park to house =?
Total distance = (distance from house to school + distance from school to park + distance from park to house)
Let p = distance from park to house
10x + 9 = (2x + 5 + z + p)
10x + 9 - 2x - 5 - z = p
8x + 4 - z
Answer:
Option C. 
Step-by-step explanation:
we know that
![A=\frac{P[(1+r)^{n} -1]}{r(1+r)^{n}}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7BP%5B%281%2Br%29%5E%7Bn%7D%20-1%5D%7D%7Br%281%2Br%29%5E%7Bn%7D%7D)
we have
substitute in the formula
![A=\frac{400[(1+0.00625)^{72} -1]}{0.00625(1+0.00625)^{72}}\\ \\A=\frac{226.446972}{0.009788}\\ \\A=\$23,134.61](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B400%5B%281%2B0.00625%29%5E%7B72%7D%20-1%5D%7D%7B0.00625%281%2B0.00625%29%5E%7B72%7D%7D%5C%5C%20%5C%5CA%3D%5Cfrac%7B226.446972%7D%7B0.009788%7D%5C%5C%20%5C%5CA%3D%5C%2423%2C134.61)
The prediction is 193.86 lb.
Substituting 73 for x, we have:
-102.3923 + 4.0582*73 = 193.86
