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ValentinkaMS [17]

3 years ago

14

Help please

1 answer:

exis [7]3 years ago

8 0

Answer:

You can put this solution on YOUR website! 5X - 20 = 10 * X 5X - 20 = 10X Subtract 5x from each side-20 = 5X Divide each side by 5-4 = X. Let's make sure it works... 20 less than five times a number (-20-20) is equal to the product of ten and that number (10 * -4)

Step-by-step explanation:

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(2b + 3r) + (4b+ r)

Pavlova-9 [17]

Let's simplify step-by-step.
<span><span><span><span>2b</span>+<span>3r</span></span>+<span>4b</span></span>+r</span>

Combine Like Terms:
<span>=<span><span><span><span>2b</span>+<span>3r</span></span>+<span>4b</span></span>+r
</span></span><span>=<span><span>(<span><span>2b</span>+<span>4b</span></span>)</span>+<span>(<span><span>3r</span>+r</span>)
</span></span></span><span>=<span><span>6b</span>+<span>4r</span></span></span>

Answer:<span>=<span><span>6b</span>+<span>4<span>r</span></span></span></span>

4 0

3 years ago

the area of a rectangle is 188 meters squared .find the length of the rectangle if the width is 4 meters, using the formula A=lw

sergiy2304 [10]

A = LW
A = 188
W = 4

188 = 4L
188/4 = L
47 = L....so the length is 47 meters

5 0

3 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

3 years ago

What is m∠FAD?<br><br><br> 48°<br><br> 42°<br><br> 52°<br><br> 38°

kirill [66]

Looks like 52° to me

4 0

3 years ago

3(5-9b)+11=-244 solve for b

natta225 [31]

15-27b+11=-244
26-27b=-244
-27b=-270
b=10

3 0

3 years ago

Read 2 more answers