Answer:
(p ∧ q)’ ≡ p’ ∨ q’
Step-by-step explanation:
First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.
p ∧ q
t t t
t f f
f f t
f f f
next step is getting the opposite
(p∧q)'
<em>f</em>
<em> t</em>
<em> t</em>
<em> t</em>
Then we get p' V q', V is true (t) when the first or the second is true.
p' V q'
f <em>f</em> f
f <em>t</em> t
t <em>t</em> f
t <em>t</em> t
Let's compare them, ≡ is true if the first is equal to the second one.
(p∧q)' ≡ (p' V q')
<em>f f </em>
<em> t t</em>
<em> t t</em>
<em> t t</em>
Both are true, so
(p ∧ q)’ ≡ p’ ∨ q’
2y + 4 + 5y + 8=
7y + 4 + 8=
7y + 12=
Answer:
x = -7 ±3i
Step-by-step explanation:
(x+7)^2+9=0
Subtract 9 from each side
(x+7)^2+9-9=0-9
(x+7)^2=-9
Take the square root of each side
sqrt((x+7)^2) = ±sqrt(-9)
We know sqrt(ab) = sqrt(a) sqrt(b)
x+7 = ±sqrt(-1) sqrt(9)
We know that sqrt(-1) is the imaginary number i
x+7 = ±i *3
x+7 =±3i
Subtract 7 from each side
x+7-7 = -7 ±3i
x = -7 ±3i
Participants = 60
.
First round:
1/3 of 60 = 20
or
60 x 1/3
= 60/3
= 20
60 - 20 = 40
There are 20 participants that are eliminated on the first sound and 40 participants to move on to the second sound.
.
Participants = 40
Second round:
1/4 of 40 = 10
or
40 x 1/4
= 40/4
= 10
40 - 10 = 30
There are 10 participants that are eliminated on the second round and 30 participants that is moving on to the next round.
.
Participants = 30
Third round:
1/6 of 30 = 5
or
30 x 1/6
= 30/6
= 5
30 - 5 = 25
There are 5 participants that are eliminated on the third round and 25 participants to move on to the fourth round.
:)
First you want to find the area of the square, which would be 121. ( 11 x 11 )
Next you want to find the area of the circle, 78.54 ((pi)5^2)
Last, you want to subtract the area of the circle, from the area of the square that is shaded. Youre left with 42.46
Hope this helped
