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Travka [436]
3 years ago
14

Can someone help me solve the systems of linear equations? x + 3y = -4x + y = 2

Mathematics
1 answer:
ycow [4]3 years ago
3 0
Y=-1
X= 3


This is the answer. If u want to see the work t is on the photo being attached
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Help show work please
pantera1 [17]
We want to get rid of the stuff in the denomenator

gcd of the denomenator is 2x
but wait, we can get rid of the deonmenator in the numerator by multiplying by 4x

muliplty the whole thing by  4x/4x

we get \frac{x(x^2)}{4(2)+2(x+4)}=\frac{x^3}{2x+16}
3 0
3 years ago
Given the function f(x)=-x+3, find the value of f(13).
Otrada [13]

F(13) means x equals 13.

Replace x in the equation with 13 and solve:

-13 + 3 = -10

F(13) = -10

3 0
3 years ago
Read 2 more answers
Help!! math algebra 1
andre [41]

Answer:

-ab/1

Step-by-step explanation:

The multiplicative inverse of x/y is y/x, because when multiplied it equals 1.

x/y time y/x = xy/xy, which equals one.

In this case, -1/ab times -ab/1 = -1ab/-1ab, which equals one.

6 0
3 years ago
The table shows the temperature (y) at different altitudes (x).
Shtirlitz [24]

Answer/Step-by-step explanation:

2. Using two pairs of values, (0, 59) and (2,000, 51),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{51 - 59}{2,000 - 0} = \frac{-8}{2,000} = -\frac{1}{250}

3. The y-intercept is the value of y when x = 0. Thus, x = 0, when y = 59. Therefore,

y-intercept (b) = 59

4. To write an equation in slope-intercept form, simply substitute m = -¹/250, and b = 59, in y = mx + b

✅y = -\frac{1}{250}x + 59

5. Substitute x = 5,000 in y = -\frac{1}{250}x + 59.

y = -\frac{1}{250}(5,000) + 59

y = -20 + 59

y = 39

At an altitude of 5,000 ft, temperature would be 39°F

3 0
3 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
4 years ago
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