The dimensions of the rectangle will be 6 inches and 12 inches.
<h3>What is the area of the rectangle?</h3>
Let L be the length and W be the width of the rectangle.
Then the area of the rectangle will be
Area of the rectangle = L × W square units
The length of a rectangular poster is 9 more inches than half its width.
L = W/2 + 9
The area of the poster is 72 square inches. Then we have
72 = L × W
72 = (W/2 + 9) × W
144 = (W + 18) × W
144 = W² + 18W
W² + 18W - 144 = 0
Then the factor of the equation will be
W² + 18W - 144 = 0
W² + 24W - 6W - 144 = 0
W(W + 24) - 6(W + 24) = 0
(W + 24)(W - 6) = 0
W = -24, 6
The width of the rectangle is 6 inches. Then the length of the rectangle will be
L = 6/2 + 9
L = 3 + 9
L = 12 inches
The dimensions of the rectangle will be 6 inches and 12 inches.
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Answer:
1 box of paper with 3 ink cartridges
Step-by-step explanation:
$100 total
$24.99+19.99(3)= $84.96 (4 ink cartridges would be over the allotted amount)
Answer:
Step-by-step explanation:
The area of a rectangle is equal to 
, where 
is the length of the rectangle and 
is the width of the rectangle. In a rectangle, opposite sides are equal.
Therefore, we can write the following system of equations:
Expand the first equation:
Substitute the second equation into the first (
):
Solving for 
:
B
Look at the pattern, they all go up by 0.5
For example, 0.5+0.5=1.0, and so fourth
Have a great day!
Answer:
L=10cm , W=30cm
Step-by-step explanation:
First use the given that W=10+2*L
Use P=2W+2L=80, substitute W in the perimeter formula
2(10+2L)+2L=80 and solve for L,
20+4L+2L=80 isolate variable L and combine like terms,
6L=80-20,
L=10, so W=10+2*10=10+20=30
