Answer:
Part (a) The point estimate of the proportion of adults aged 18 to 29 who use the Internet is 0.9498.
Part (b) The point estimate of the proportion of adults aged 30 to 49 who use the Internet is 0.8896.
Part (b) Estimate of the proportion of population who use the Internet is 0.7624.
Step-by-step explanation:
Consider the provided information.
Part (a) point estimate of the proportion of adults aged 18 – 29 who use the Internet
The results showed that 454 out of 478 adults aged 18-29 answered yes;

The point estimate of the proportion of adults aged 18 to 29 who use the Internet is 0.9498.
Part (b) Develop a point estimate of the proportion of adults aged 30-49
741 out of 833 adults aged 30-49 answered yes;

The point estimate of the proportion of adults aged 30 to 49 who use the Internet is 0.8896.
Part (c) Suppose your target population of interest is that of all adults (18 years of age and over). Develop an estimate of the proportion of that population who use the Internet.


Estimate of the proportion of population who use the Internet is 0.7624.
Answer:
Step-by-step explanation:
The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Given a quadratic function for the transformations given the function f(x) = x²
If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value
- Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)
Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Learn more here: brainly.com/question/15381183
Area of the base = 1/2 * 10 * 5sqrt3 = 25 sqrt3
Total surface area = 25 sqrt3 + 3 * 1/2 * 10 * slant height = 214.5
25 sqrt3 + 15h = 214.5
15h = 214.5 - 25 sqrt3
h = (214.5 - 25sqrt3() / 15
= 11.41 cm to nearest hundredth