Alternate exterior angles are the pair of angles that lie on the outer side of the two parallel lines but on either side of the transversal line. Illustration: ... Notice how the pairs of alternating exterior angles lie on opposite sides of the transversal but outside the two parallel lines.
Answer:
<u>The system has two solutions:</u>
<u>x₁ = 5 ⇒ y₁ = -10</u>
<u>x₂ = -2 ⇒ y₂ = 11</u>
Step-by-step explanation:
Let's solve the system of equations, this way:
y = -3x + 5
y = x ² - 6x - 5
Replacing y in the 2nd equation:
y = x ² - 6x - 5
-3x + 5 = x ² - 6x - 5
x ² - 3x - 10 = 0
Solving for x, using the quadratic formula:
(3 +/- √(9 -4 * 1 * -10))/2 * 1
(3 +/- √9 + 40)/2
(3 +/- √49)/2
(3 +/- 7)/2
x₁ = 10/2 = 5
x₂ = -4/2 = -2
x₁ = 5 ⇒ y₁ = -10
x₂ = -2 ⇒ y₂ = 11
<u>As we can see the system has two different solutions</u>
4x² - 12x = 7
- 7 - 7
4x² - 12x - 7 = 0
4x² + 2x - 14x - 7 = 0
2x(2x) + 2x(1) - 7(2x) - 7(1) = 0
2x(2x + 1) - 7(2x + 1) = 0
(2x - 7)(2x + 1) = 0
2x - 7 = 0 or 2x + 1 = 0
+ 7 + 7 - 1 - 1
2x = 7 2x = -1
2 2 2 2
x = 3¹/₂ or x = ⁻¹/₂
Answer:
5 miles
Step-by-step explanation:
14 - 8.37 means his car still had 5.63 gallons
27.6/5.63 = 4.9
Isolate the variable by dividing each side by factors that don't contain the variable.
-6x-15+15=4x+35+15
-6x=4x+50
(Subtract 4 on both sides)
-10x=50
(Divide by 10 on both sides)
x=5