Which of these is a simplified form of the equation 8y + 4 = 6 + 2y + 1y?

2 answers:

3 0

The first one would be the right one!

you just take all the y one side and the numbers on one side
so 8y+4= 6+3y

now 8y-3y= 6-4

therefore 5y = 2

!!

Lena [83]3 years ago

3 0

So, with this I'm pretty sure you have to get all variables and all normal numbers on the same sides SO if 8y+4=6+2y+1y, then you must get the 4 over to 6 so then the equation would be, 8y=-4+6+2y+1y and the 2y and 1y (or 3y) must change to the other side so then it would be 8y-3y=-4+6. Then you just simplify to 5y=2. Therefore, your answer is A.

Steps
8y+4=6+2y+1y
8y=-4+6+2y+1y
8y-3y=-4+6
∴ 5y=2

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joe weighs 20lbs.less yhantwice jeffs weight.if jeff would gain 10lbs.,then together they wouldweigh 250lbs. how much does each

masya89 [10]

So,

Let x represent Joe's weight and y represent Jeff's weight.

"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250

We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250

Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250

We will use Elimination by Substitution.
2y - 20 + y + 10 = 250

Collect Like Terms.
3y - 10 = 250

Add 10 to both sides.
3y = 260

Divide both sides by 3.
$Jeff's\ weight = 86 \frac{2}{3} \ lbs.$

Substitute again.
$x = 2(86 \frac{2}{3} )-20$

Multiply.
$x = 173 \frac{1}{3} -20$

Subtract.
$Joe's\ weight = 153 \frac{1}{3}\ lbs.$

Check.

"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.

$Joe's\ weight\ is\ 153 \frac{1}{3} \ lbs.$
$Jeff's\ weight\ is\ 86 \frac{2}{3} \ lbs.$

3 0

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Express 72 as a percentage of 92

dolphi86 [110]