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1 year ago

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Jaime has 21 red balloons and 28 blue balloons. He wants to make balloon bouquets. Each bouquet must have the same number of bal

loons in it. Without mixing balloons, what is the greatest number of balloons that Jaime can put in each bouquet?

1 answer:

likoan [24]1 year ago

5 0

Answer:

7

Step-by-step explanation:

We need to find the common number that goes into both numbers and thus we get 7

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please help me it is URGENT pls the first one is solve and the 2nd one is simplify I will give u lots of points thank you

klasskru [66]

I.) (5x+3)/4-(2x-4)/3=5
Clear fractions:
3·((5x+3)/4)=15x+9
4·((2x-4)/3)=8x-16
15x+9-(8x-16)=5
15x+9-8x+16=5
Combine like terms:
7x+25=5
7x=-20
x=-20/7

II.) (3/11)·(5/6)-(9/12)·(4/3)+(5/13)·(6/15)
Remember PEMDAS
So first multiply:
3/11·5/6=15/66
9/12·4/3=3/3·1/1=3/3=1
5/13·6/15=1/13·6/3=6/39=2/13
(15/66)-1+(2/13)
Combine:
15/66-1/1=15/66-66/66=-51/66
-51/66+2/3=-51/66+44/66=-7/66
Answer: -7/66 :)

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