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3 years ago

HELP ASAP I WILL GIVE BRAINLIST

Mathematics

1 answer:

VikaD [51]3 years ago

6 0

Answer:

33.51 cm

Step-by-step explanation:

240/360 = 2/3 (Arc length is 2/3 of the total circumference)

C = 2 $\pi$ r ( Calculate the total circumference)

C = 2(8) $\pi$

C = 50.265

2/3(50.265) (Take 2/3 of the circumference. times 2 divide by 3)

33.51

Use a calculator and leave the answer to C and then multiply and divide. You get a more precise answer.

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Suppose that farmers grew an unexpectedly large number of tomatoes this year. How would this increase production affect the pric

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It would decrease the price of tomatoes. As supply rises, demand lowers and the cost lowers with it.

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3 years ago

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What is an equation in slope-intercept form of the line that passes through the points (−2, −2) and (1, 7)? A.y = 4x + 3 B.y − 7

antoniya [11.8K]

Answer:

C.y = 3x + 4

Step-by-step explanation:

We have two points, so we can find the slope

m = (y2-y1)/ (x2-x1)

= (7--2)/ (1--2)

= (7+2)/(1+2)

= 9/3

The slope is 3

We can find the point slope form of the line

y-y1 = m(x-x1)

y-7 = 3(x-1)

Distribute

y-7 =3x-3

Add 7 to each side

y-7+7 = 3x-3+7

y = 3x+4

This is in slope intercept form (y=mx+b)

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3 years ago

Claudia has 6543 followers on FaceBook. She wants to divide her followers into groups of three. How many groups of three will Cl

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3 years ago

Help me with differentation and integration please!!

Marina86 [1]

Answer:

See below

Step-by-step explanation:

$\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x$

Recall

$\dfrac{d}{dx}\tan x=\sec^2$

Using the chain rule

$\dfrac{dy}{dx}= \dfrac{dy}{du} \dfrac{du}{dx}$

such that $u = \tan x$

we can get a general formulation for

$y = \tan^n x$

Considering the power rule

$\boxed{\dfrac{d}{dx} x^n = nx^{n-1}}$

we have

$\dfrac{dy}{dx} =n u^{n-1} \sec^2 x \implies \dfrac{dy}{dx} =n \tan^{n-1} \sec^2 x$

therefore,

$\dfrac{d}{dx}\tan^3 x=3\tan^2x \sec^2x$

Now, once

$\sec^2 x - 1= \tan^2x$

we have

$3\tan^2x \sec^2x = 3(\sec^2 x - 1) \sec^2x = 3\sec^4x-3\sec^2x$

Hence, we showed

$\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x$

================================================

For the integration,

$\int \sec^4 x\, dx$

considering the previous part, we will use the identity

$\boxed{\sec^2 x - 1= \tan^2x}$

thus

$\int\sec^4x\,dx=\int \sec^2 x(\tan^2x+1)\,dx = \int \sec^2 x \tan^2x+\sec^2 x\,dx$

and

$\int \sec^2 x \tan^2x+\sec^2 x\,dx = \int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx$

Considering $u = \tan x$

and then $du=\sec^2x\ dx$

we have

$\int u^2 \, du = \dfrac{u^3}{3}+C$

Therefore,

$\int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx = \dfrac{\tan^3 x}{3}+\tan x + C$

$\boxed{\int \sec^4 x\, dx = \dfrac{\tan^3 x}{3}+\tan x + C }$

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3 years ago

Solve x^2-8x=3 by completing the square. Which is the solution set of the equation

kkurt [141]

Answer:

{-0.36, 8.36) to the nearest hundredth.

Step-by-step explanation:

x^2 - 8x = 3

(x - 4)^2 - 16 = 3

(x - 4)^2 = 19

Taking square roots:

x - 4 = +/- √19

x = 4 +/- √19

x = {-0.36, 8.36} to nearest 1/100.

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