Using the following two points, find the slope: ( -1, 5 ) and ( 2, -3 ).

Question 1 8x + y = 2020: Solve for y.

Katarina [22]

Answer:

y = -8x+2020

Step-by-step explanation:

8x + y = 2020

Subtract 8x from each side

8x-8x + y = -8x+ 2020

y = -8x+2020

8 0

3 years ago

Read 2 more answers

rachel bought one double pack of CDs for $20. this is $4 less than 3/4 the cost of a triple pack of CDs. what is the price of a

Sophie [7]

The price of a triple pack of Cds is $30.

6 0

3 years ago

A. Write two explicit formulas for arithmetic sequences.

IgorLugansk [536]

Explicit formulas for arithmetic sequences are derived from terms in arithmetic sequences. It helps to find each term in arithmetic progression easily. The arithmetic progression is a1, a2, a3, ..., an. where the first term is denoted as 'a', we have a = a1, and the tolerance is denoted as 'd'. The tolerance formula is d = a2 - a1 = a3 - a2 = an - an - 1. The nth term of the arithmetic progression represents the explicit formula for the arithmetic progression.

Explicit formula: an= a + (n − 1) d

Explicit formula: Sn = n/2 [2a+(n-1) d]

Where,

nth term in the arithmetic sequence

a = first term in the arithmetic sequence

d = difference (each term and its term difference) previous term, i.e., d = an-an-1

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7 0

1 year ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

3 0

3 years ago

(I don't have much points so I can't provide you with a huge amount but I do need help. I do also need the step by step definiti

cluponka [151]

Answer:

this is my answer

Step-by-step explanation:

The expression P(−1.33<z<1.59) represents the area under the standard normal curve above a given value oz. Use your standard normal table to find the indicated area. Use a sketch of the standard normal curve with the appropriate area shaded to help find the answer.What is the value of P(−1.33<z<1.59) between the given values oz?Express your answer rounded to 4 decimal places.The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 100.Sofia scored 632 on the test.What percent of students scored below Sofia?Round your answer to the nearest hundredth.The scores on a standardized test are normally distributed with a mean of 500 and a standard deviation of 100.Benita scored 432 on the test.What percent of students scored below Benita?Round your answer to the nearest hundredth.The expression P(z<1.00) represents the area under the standard normal curve below a given value oz. Use your standard normal table to find the indicated area. Use a sketch of the standard normal curve with the appropriate area shaded so this is going to let you find the answer.

5 0

2 years ago