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3 years ago

10

Please help answer this if your able two :)) ♡

2 answers:

andreev551 [17]3 years ago

8 0

Answer:

Y + 3= 3/4( x - 7)

ivann1987 [24]3 years ago

4 0

Answer: y = 3/4 + 8.25

Step-by-step explanation:

1. You already know the slope, 3/4, and the coordinates (-7,3). We could plug these into a y=mx+b equation: 3=3/4(-7) + b

2. Next you need to solve for b. Then you get your answer of 8.25. (I attached my work for that)

3. You plug in 8.25 as your y-intercept or b: y=3/4 + 8.25

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When a fridge is imported, a customs value of 10% must be paid for its value. If the value of the fridge after paying the custom

Akimi4 [234]

Answer:

55000×100/90

61,111.111

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2 years ago

A number is chosen at random from 1 to 50. find the probability of selecting numbers greater than 3 and less than 39. How to sol

liq [111]

Solve than first chose letter and bind

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2 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

a

$336.04 < \mu < 443.96$

b

The margin of error will increase

c

The margin of error will decreases

d

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

So

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

4 0

3 years ago

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an

marishachu [46]

Answer: $x+x^2+x^3+x^4$

Step-by-step explanation:

As per given,

Number of wives = $x$

Number of sacks = $x (\text{Number of wives} )= x\times x = x^2$

Number of cats = $x(\text{Number of sack})$ $= x \times x^2=x^3$

Number of kits = $x(\text{Number of cats} )=x\times x^3=x^4$

Now , the total number of kits, cats, sacks, and wives going to St. Ives = $x+x^2+x^3+x^4$

Hence, the required ex[pression: $x+x^2+x^3+x^4$

5 0

3 years ago

How do you write this from least to greatest? 1.265,1.256,1.268

n200080 [17]

Answer:

1.256, 1.265, and 1.268

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers