Answer:
// A optimized school method based C++ program to check
// if a number is composite.
#include <bits/stdc++.h>
using namespace std;
bool isComposite(int n)
{
// Corner cases
if (n <= 1) return false;
if (n <= 3) return false;
// This is checked so that we can skip
// middle five numbers in below loop
if (n%2 == 0 || n%3 == 0) return true;
for (int i=5; i*i<=n; i=i+6)
if (n%i == 0 || n%(i+2) == 0)
return true;
return false;
}
// Driver Program to test above function
int main()
{
isComposite(11)? cout << " true\n": cout << " false\n";
isComposite(15)? cout << " true\n": cout << " false\n";
return 0;
}
Explanation:
Name servers.
-----------------------------------------------------------
Here are some.
- <html></html> This is the root element tag. ...
- <head></head> ...
- <title></title> ...
- <body></body> ...
- <h1></h1> ...
- <p></p> ...
- <a></a> ...
- <img></img>
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Answer:
C. Mean
Explanation:
Mean = (∑
)/N
Median = central values when data is sorted
Mode = most repeated value
Standard deviation = 
In standard deviation, formula you may see that deviation is being calculated from the mean (central location). But here we take square of the value before adding all of them.
But if we just take
, it would be equal to zero.
<u>EXAMPLE</u>
Take 4, 9, 5 as data
mean = (4+9+5)/3 = 18/3 = 6
sum of deviations from mean = (4-6)+(9-6)+(5-6) = (-2)+(3)+(-1) = 0
Explanation:
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Hope this answer is helpful