$230+($45x$0.42=248.90
That is the equation to solve it.
Answer:
A. The value of the sample proportion is 0.4
B. The standard error of the sample proportion is 0.02619
C. 0.3487 ≤ p ≤ 0.4513
Step-by-step explanation:
The value of the sample proportion p' is calculated as:

Where x is the number of success in the sample or the number of students that use a laptop in class to take notes and n is the size of the sample or 350 students.
On the other hand, the standard error SE of the sample proportion is calculated as:

so, replacing the values, we get:

Finally, an approximate 95% confidence interval for the true proportion p is calculate as:

Where 1-α is equal to 95%, so
is equal to 1.96. Then, replacing the values we get:

0.4 - 0.0513 ≤ p ≤ 0.4 + 0.0513
0.3487 ≤ p ≤ 0.4513
Answer:
4z+11
Step-by-step explanation:
11z-7z=4z
17-6=11
Multiply by the reciprocal, 4/3
A) is 28 response are recorded
B) there was only 24 students polled
C) A possible explanation for having more responses recorded than students polled is that they some may have played more than one sport.