Hwy friend
Let's figure this out.
5+7+4+4= 20 total students
4/20 students have hazel eyes
6/20 students do not have hazel eyes
16 / 20 =.8
80% chance that 1 is not hazel
80% that the 2nd isn't hazel
To find the probability that both will not be hazel you must multiply:
80% by 80% (.8 * .8)
.8 *.8 = .64
There is a 64% chance both of the selected students wont have hazel eyes.
Conditions for side lenghts for triangle:
a<b+c and
b<c+a and
c<a+b
so we check all posibilities:
A) 2+5=7 we can see that one condition is not fulfilled so they can't be side lenghts of triangle
B) 9<14+17
14<9+17
17<14+19
All conditions are fulfilled so they can be side lenghts of triangle
C)7<17+24
17<7+24
24<17+7
All conditions are fulfilled so they can be side lenghts of triangle
D)5<12+13
12<5+13
13<5+12
All conditions are fulfilled so they can be side lenghts of triangle
Answer:
it’s 15x+30y-220
Step-by-step explanation:
Because you distribute and then you add the like terms
Answer:
4 7#+$+28$;;_(#(#;$('jwhdbdisjwb