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3 years ago

Find all angles and pls show steps

Mathematics

1 answer:

Ghella [55]3 years ago

7 0

Answer:

Both angles have a measure of 134degrees, y = 27degrees.

Step-by-step explanation:

As per what is given in the problem:

There are 2 parallel lines, both are intersected by a transversal.

Remember the theorem, when two parallel lines are intersected by a transversal, then the alternate exterior angles are congruent.

The is meanse that:

3y + 53 = 7y - 55

Solve using inverse operations:

3y + 53 = 7y - 55

+55 +55

3y + 108 = 7y

-3y -3y

108 = 4y

/4 /4

27 = y

Now, substitute back in to find the value of the angle:

3y + 53

y = 27

3 ( 27 ) + 53

81 + 53

= 134

Since the angles are alternate exterior, they are congruent, hence both angles have a measure of 134degrees.

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bagirrra123 [75]

Step-by-step explanation:

Cost of white shirt=$15

Cost of tie-dye shirt = $20

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Cost of tie-dye shirts = 300×20= $6000

Verification:

3000+6000=$9000 proved!

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2 years ago

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Answer<br><br> -10 – (-2) =

Allisa [31]

Answer:

Step-by-step explanation:

- (-2) is the same as + 2

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3 years ago

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What is the tenth term in the sequence 9, 13, 17, 21, 25…?

Zinaida [17]

Answer:

Step-by-step explanation:

9, 13, 17, 21, 25

We are adding 4 each time

9+4 = 13

13+4 =17

17+4 = 21

The common difference =4

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The formula is

an = a1+d(n-1) where n is the term number

an = 9+4(n-1)

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= 45

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2 years ago

Can someone pls help me 2-7 thank u :)

kolbaska11 [484]

2. 27
3. 13
4. 35
6. 22
7. 60

I was unable to help with 5 because of the plot box!! Hope this helps

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3 years ago

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The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago

Find all angles and pls show steps ​

Find all angles and pls show steps