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3 years ago

Help Need Answer Plz!!

Mathematics

1 answer:

sammy [17]3 years ago

5 0

Answer:

MT congruent to CA

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Out of 400 applicants for a job, 179 are female and 72 are female and have a graduate degree. Step 2 of 2 : If 118 of the applic

Dafna11 [192]

Answer:

36/59 or 0.610

Step-by-step explanation:

P(female and degree)/P(degree)

72/118

36/59

0r 0.610

7 0

2 years ago

(t,-3) and (2,6); Slope = -1

tangare [24]

-1= $\frac{Δy}{Δx}$
-1= $\frac{6-(-3)}{2-t}$
t-2=9
t=11

4 0

2 years ago

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

2 years ago

Sophia earned $294 in 24 hours. How many dollars did she earn per hour?

Vadim26 [7]

Answer:

$12.25

Step-by-step explanation:

Step 1:

$294 : 24 Ratio

Step 2:

$294 ÷ 24 Divide

Answer:

$12.25

Hope This Helps :)

6 0

2 years ago

Read 2 more answers

Please help!!!!!!!!!!!¡

Daniel [21]

Your answer would be ( -12/5 x + 2 )

6 0

2 years ago