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enyata [817]
3 years ago
13

Rewrite the following expression x^9/7

Mathematics
1 answer:
Alexxx [7]3 years ago
4 0

Answer:

\sqrt[7]{x^9}

Step-by-step explanation:

its kinda difficult for me to explain so i guess just use this equation next time:

x^{m/n} = \sqrt[n]{x^m}

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Answer for the problem of 2 1/5+1 3/4
lions [1.4K]
The answer to this question is 3 19/20
4 0
4 years ago
Write this expression so that its denominator, if any, is a positive integer.<br> 2/(3+sqrt(7))
Tanzania [10]

Answer:

The Answer is 3 - sqrt7

Step-by-step explanation:

2/3 + sqrt7   the starting equation

You multiply it by the conjugate which is 3 - sqrt7

= 2(3 - sqrt7) / (3 + sqrt7) (3 - sqrt7)  the equation after you multiply by 3 - sqrt7

(3 + sqrt7) (3 - sqrt7) = 2

= 2(3 - sqrt7) / 2    the equation after you simplify (3 + sqrt7) (3 - sqrt7)

Divide out the 2's

= 3 - sqrt7/1    the equation after you divide out the 2's

= 3 - sqrt7  is THE ANSWER

7 0
2 years ago
In a group of college students, the ratio of men to women is 3:1 (i.e., 3 to 1). In a recent survey, 40% of the men in this grou
katovenus [111]

Answer:

0.3875

Step-by-step explanation:

Given that in a group of college students, the ratio of men to women is 3:1 (i.e., 3 to 1). In a recent survey, 40% of the men in this group selected hiking as their favorite outdoor activity whereas 35% of the women in the group selected hiking as their favorite outdoor activity

From the above information we find that

P(Men) = 0.75 and P(women) = 0.25 (since men:women = 3:1)

Out of men prob for not selecting hiking as their favorite outdoor activity

=1-0.6 = 0.4

Out of women prob for not selecting hiking as their favorite outdoor activity

=1-0.35 = 0.65

Prob for a randomly selected person that hiking is not his/her favorite outdoor activity = Prob (man and not selected activitiy) + P(women and not selected activity) (since men and women are mutually exclusive and exhaustive)

=0.75(0.4)+0.25(0.35)\\= 0.30+0.0875\\\\=0.3875

6 0
3 years ago
A survey is planned to estimate the proportion of voters who support a proposed gun control law. The estimate should be within a
laila [671]

Complete Question

A survey is planned to estimate the proportion of voters who support a proposed gun control law. The estimate should be within a margin of error of ±5% with 90% confidence, and we do not have any prior knowledge about the proportion who might support the law. How many people need to be included in the sample?

Round your answer up to the nearest integer.

sample size = _____

Answer:

The sample size is n = 271    

Step-by-step explanation:

From the question we are told that  

   The margin of error is  E = 5% = 0.05

Generally given that there was no prior knowledge about the proportion of who might support the law, we will assume the sample proportion to be  

     \^ p =  0.5

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>   n = [\frac{1.645 }{0.05} ]^2 * 0.5 (1 - 0.5 )

=>   n = 271    

5 0
3 years ago
PLEASE HELP THIS IS MATH 171 the topic is partial fraction decomposition
mars1129 [50]

What do you mean? Where is the question?

8 0
2 years ago
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