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Luda [366]
3 years ago
13

Multiply (2x-5)(x+7) and show work please

Mathematics
2 answers:
AVprozaik [17]3 years ago
7 0
<span>(2x-5)(x+7)  

Distribute .....

</span><span>(2x-5) (x+7) 

2x^2 + 14x - 5x - 35 

Combine like terms....

2x^2 + 9x - 35 is the answer </span>
oksian1 [2.3K]3 years ago
5 0
For this problem, use the FOIL method
First, outer, inner, last
First, multiply the first term with the third term, 2x times x is 2x^2
Next, multiple the first term with the last term, 2x times 7 is 14x                        Now, multiply the second term with the third term, -5 times x is -5x
Then, multiply the second term with the fourth term -5 times 7 is -35
Finally add all these answers up - 2x^2+14x+(-5x)+(-35)
Combine like terms to get your answer 14x+(-5x)=9x
2x^2+9x-35

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what's the final volume of a gas with an initial volume of 75ml if the pressure decreases from 300ml to 200ml? A. 50.0ml B.112.5
aivan3 [116]
300 ml ... 200 ml
75 ml ... x = ?

If you would like to know what is the final volume of a gas, you can calculate this using the following steps:

300 * x = 200 * 75     /300
x = 200 * 75 / 300
x = 50.0 ml

The correct result would be A. 50.0 ml.
8 0
3 years ago
Read 2 more answers
A parabola has its focus at (1,2) and its directrix is y=-2. the equation of this parabola could be
Oksi-84 [34.3K]
<span>x^2/8 - x/4 + 1/8 = 0 A parabola is defined as the set of all points such that each point has the same distance from the focus and the directrix. Also the parabola's equation will be a quadratic equation of the form ax^2 + bx + c. So if we can determine 3 points on the parabola, we can use those points to calculate the desired equation. First, let's draw the shortest possible line from the focus to the directrix. The midpoint of that line will be a point on the desired parabola. Since the slope of the directrix is 0, the line will have the equation of x=1. This line segment will be from (1,2) to (1,-2) and the midpoint will be ((1+1)/2, (2 + -2)/2) = (2/2, 0/2) = (1,0). Now for the 2nd point, let's draw a line that's parallel to the directrix and passing through the focus. The equation of that line will be y=2. Any point on that line will have a distance of 4 from the directrix. So let's give it an x-coordinate value of (1+4) = 5. So another point for the parabola is (5,2). And finally, if we subtract 4 instead of adding 4 to the x coordinate, we can get a third point of 1-4 = -3. So that 3rd point is (-3,2). So we now have 3 points on the parabola. They are (1,0), (5,2), and (-3,2). Let's create some equations of the form ax^2 + bx + c = y and then substitute the known values into those equations. SO ax^2 + bx + c = y (1) a*1^2 + b*1 + c = 0 (2) a*5^2 + b*5 + c = 2 (3) a*(-3)^2 + b*(-3) + c = 2 Let's do the multiplication for those expressions. So (4) a + b + c = 0 (5) 25a + 5b + c = 2 (6) 9a - 3b + c = 2 Equations (5) and (6) above look interesting. Let's subtract (6) from (5). So 25a + 5b + c = 2 - 9a - 3b + c = 2 = 16a + 8b = 0 Now let's express a in terms of b. 16a + 8b = 0 16a = -8b a = -8b/16 (7) a = -b/2 Now let's substitute the value (-b/2) for a in expression (4) above. So a + b + c = 0 -b/2 + b + c = 0 And solve for c -b/2 + b + c = 0 b/2 + c = 0 (8) c = -b/2 So we know that a = -b/2 and c = -b/2. Let's substitute those values for a and c in equation (5) above and solve for b. 25a + 5b + c = 2 25(-b/2) + 5b - b/2 = 2 -25b/2 + 5b - b/2 = 2 2(-25b/2 + 5b - b/2) = 2*2 -25b + 10b - b = 4 -16b = 4 b = -4/16 b = -1/4 So we now know that b = -1/4. Using equations (7) and (8) above, let's calculate a and c. a = -b/2 = -(-1/4)/2 = 1/4 * 1/2 = 1/8 c = -b/2 = -(-1/4)/2 = 1/4 * 1/2 = 1/8 So both a and c are 1/8. So the equation for the parabola is x^2/8 - x/4 + 1/8 = 0 Let's test to make sure it works. First, let's use an x of 1. x^2/8 - x/4 + 1/8 = y 1^2/8 - 1/4 + 1/8 = y 1/8 - 1/4 + 1/8 = y 1/8 - 2/8 + 1/8 = y 0 = y And we get 0 as expected. Let's try x = 2 x^2/8 - x/4 + 1/8 = y 2^2/8 - 2/4 + 1/8 = y 4/8 - 1/2 + 1/8 = y 4/8 - 1/2 + 1/8 = y 1/2 - 1/2 + 1/8 = y 1/8 = y. Let's test if (2,1/8) is the same distance from both the focus and the directrix. The distance from the directrix is 1/8 - (-2) = 1/8 + 2 = 1/8 + 16/8 = 17/8 The distance from the focus is d = sqrt((2-1)^2 + (1/8-2)^2) d = sqrt(1^2 + -15/8^2) d = sqrt(1 + 225/64) d = sqrt(289/64) d = 17/8 And the distances match again. So we do have the correct equation of: x^2/8 - x/4 + 1/8 = 0</span>
4 0
3 years ago
7(2+3x)+8, 12+3(8+x), and (7x+2)3+8x
suter [353]

Answer:

The first answer is 21x+22.

Second answer is 36+3x.

Third answer is 29x+6.

Step-by-step explanation:

I just simplified

5 0
2 years ago
What is d if <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3d-2%7D%7B8%7D%20%3D%20-d%2B16%5Cfrac%7B1%7D%7B4%7D" id="TexFormula1" t
Harlamova29_29 [7]

Answer: d=12

Step-by-step explanation:

\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}

Multiply both parts of the equation by 8:

\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\

Divide both parts of the equation by 11:

d=12

8 0
1 year ago
What is 5/12 divided by 3/16 as a fraction?
GuDViN [60]
<span>The answer is
= 20/9
=2 2/9</span>
8 0
3 years ago
Read 2 more answers
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