For this case we have:
Let x be the variable that belongs to the real numbers. Then, all reals less than 70 can be expressed as:
The tip of the inequality is directed to the real numbers, since they tell us that they are less than 70, for 70 the inequality remains open.
Answer:
Answer:
The bounded area is 5 + 5/6 square units. (or 35/6 square units)
Step-by-step explanation:
Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)
Such that f(x) > g(x) in the given interval.
This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).
We want to find the area bounded by:
f(x) = y = x^2 + 1
g(x) = y = x
x = -1
x = 2
To find this area, we need to f(x) - g(x) between x = -1 and x = 2
This is:
We know that:
Then our integral is:
The right side is equal to:
The bounded area is 5 + 5/6 square units.