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2 years ago

If two angle of a right angle triangle are in the ratio 1:2,find them

Mathematics

2 answers:

Oksanka [162]2 years ago

5 0

Answer:

let the angles be x,2x

=>90+x+2x=180

=>3x=90

=>x=30

so, the angles are 30,60

disa [49]2 years ago

4 0

let the angles be x,2x

=>90+x+2x=180

=>3x=90

=>x=30

so, the angles are 30,60

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I need help please please

Aliun [14]

Answer:

y= -4/3x +8

Step-by-step explanation:

well first you got to simply for equation

4x +3y = 24

so you subtract 4x to both sides and that gives you : 3y= -4y +24

then you divide everything by 3

and that leaves you with : y= -4/3x +8

and the graph just put a dot on 8 on the y axis then go down -4 and left 3

your welcome!!!!!!!!1

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2 years ago

Katerina’s digital camera takes low resolution photos that use 0.5 MB of memory, and high resolution photos that use 2.5 MB of m

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2 years ago

Need ASAP 20 points !

AlladinOne [14]

Answer:

X = 116

Step-by-step explanation:

Total heptagon angle = 900

124 + 120 + 122 + 136 + 144 + 138 = 784

900 - 784 = 116

4 0

2 years ago

What’s the distributive property of 17 x 8

Kamila [148]

Answer:

Step-by-step explanation:

Remember simple multiplication? Write the problem with 17 at the bottom:

* 1 7

----------

5 6 <-- this is 8*7

8 0 <-- this is 8*10 [we sometimes just shift and don't write the 0]

-------

1 3 6

So, 8*17 is the same as 8*10 + 8*7.

3 0

2 years ago

Read 2 more answers

X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$

Part b.

Consider V(3X + 2Y)

$\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}$

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

$3 X+2 Y \sim N(18,77)$

Thus,

$P(3 X+2 Y < 18)=0.5$

Part d.

Consider P(3X + 2Y < 28)

$Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}$

$\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}$

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0

1 year ago

If two angle of a right angle triangle are in the ratio 1:2,find them​

If two angle of a right angle triangle are in the ratio 1:2,find them